Answer:
1974.6 feets
Step-by-step explanation:
The plane's altitude is : h + 100 feets
To obtain h, according to the attached picture ;
We can use trigonometry :
Tan θ = opposite / Adjacent
Opposite = h ; adjacent = 3000 feets
Tan 32° = h / 3000
h = 3000 * 0.6248693
h = 1874.6080
Plane's altitude :
h + 100 feets
(1874.6080 + 100) feets
= 1974.6 feets
I believe the answer is B right??? and why are there two 25% ?
Answer:
5.74 = x
Step-by-step explanation:
(whole secant) * (external part) = (tangent)^2
(8+3) * 3 = x^2
11*3 = x^2
33 = x^2
Take the square root
sqrt(33) = sqrt(x^2)
5.744562647 = x
Round to the nearest hundredth
5.74 = x
Answer:
5.55% of broilers weigh between 1143 and 1242 grams
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 1511, \sigma = 198](https://tex.z-dn.net/?f=%5Cmu%20%3D%201511%2C%20%5Csigma%20%3D%20198)
What proportion of broilers weigh between 1143 and 1242 grams?
This is the pvalue of Z when X = 1242 subtracted by the pvalue of Z when X = 1143.
X = 1242
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{1242 - 1511}{198}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B1242%20-%201511%7D%7B198%7D)
![Z = -1.36](https://tex.z-dn.net/?f=Z%20%3D%20-1.36)
has a pvalue of 0.0869
X = 1143
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{1143 - 1511}{198}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B1143%20-%201511%7D%7B198%7D)
![Z = -1.36](https://tex.z-dn.net/?f=Z%20%3D%20-1.36)
has a pvalue of 0.0314
0.0869 - 0.0314 = 0.0555
5.55% of broilers weigh between 1143 and 1242 grams