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suter [353]
3 years ago
5

A bag of firewood has a mass of 10.0 kilograms and a weight of

Physics
1 answer:
lorasvet [3.4K]3 years ago
8 0
90 kilograms hope this helps
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Which options correctly describe the velocity of the object represented in the graph?
kirza4 [7]
There is no graph ...
7 0
2 years ago
When two equal forces act on the same object in opposite directions, what is the net force?
sertanlavr [38]

Answer:

0

Explanation:

Forces with equal magnitudes and opposite directions cancel each other out, so the net force is 0.

6 0
3 years ago
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A man pushes a 10kg box with a constant acceleration of 5m/s2. What force is applied to the box?
drek231 [11]
FORMULA

\boxed {F = m \times a}

F = force
m = mass
a = acceleration

Using the formula

F = 10 \times 5

Multiply

\boxed {\textsf {F = 10 N}}
8 0
3 years ago
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An object 82 cm high forms a virtual image 4.1 cm high located 4.6 cm behind a mirror. Find the object distance.
ioda

Answer:

The object distance is 92 cm.  

Explanation:

let v be the image distance and h be the height of the image, let u the be the object distance and H be the height of the object.

then, the magification of the mirror is given by:

m = -v/u and m = h/H

so, -v/u = h/H

         u = -v×H/h

            = -(-4.6)×(82)/(4.1)

            = 92 cm

Therefore, the object distance is 92 cm.

8 0
3 years ago
An airplane is flying at a speed of 45 m/s when it drops a 40 kg food package to the Polar exploration team. If the plane drops
Alina [70]

To solve this problem we will apply the concepts related to energy conservation, so the potential energy in the package must be equivalent to its kinetic energy. From there we will find the speed of the package in the vertical component. The horizontal component is given, as it is the same as the one the plane is traveling to. Vectorially we will end up finding its magnitude. So,

PE = KE

mgh = \frac{1}{2}mv^2

Here,

m = Mass

g = Gravity

h = Height

v = Velocity

Rearranging to find the velocity

v = \sqrt{2gh}

Replacing,

v = \sqrt{2(9.8)(120)}

v = 48.49m/s

Using the vector properties the magnitude of the velocity vector would be given by,

|V| = \sqrt{v_x^2+v_y^2}

|V| = \sqrt{45^2+48.42^2}

|V| = 66.2m/s

Therefore the package is moving to 66.2m/s

3 0
3 years ago
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