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dlinn [17]
3 years ago
14

The effect of current electricity

Physics
1 answer:
olganol [36]3 years ago
5 0

Answer:

(3 ) friction hope this is correct

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Two positive charges q1 = q2 = 2.0 μC are located at x = 0, y = 0.30 m and x = 0, y = -0.30 m, respectively. Third point charge
Wittaler [7]

Answer:

 F = 0.111015 N

Explanation:

For this exercise the force is given by Coulomb's law

        F = k q₁q₂ / r₂₁²

we calculate the electric force of the other two particles on the charge q1

Charges q₁ and q₂

the distance between them is

          r₁₂ = y₁ -y₂

          r₁₂ = 0.30 + 0.30

          r₁₂ = 0.60 m

let's calculate

          F₁₂ = 9 10⁹ 2 10⁻⁶ 2 10⁻⁶ / 0.60 2

          F₁₂ = 1 10⁻¹ N

directed towards the positive side of the y-axis

Charges 1 and 3

Let's find the distance using the Pythagorean Theorem

             r₁₃ = RA [(0.40-0) 2 + (0-0.30) 2]

             r₁₃ = 0.50 m

            F₁₃ = 9 10⁹ 2 10⁻⁶ 4 10⁻⁶ / 0.50²

            F₁₃ = 1.697 10⁻² N

The direction of this force is on the line that joins the two charges (1 and 3), let's use trigonometry to find the components of this force

           tan θ = y / x

           θ = tan⁻¹ y / x

          θ = tan⁻¹ 0.3 / 0.4

           tea = 36.87º

    The angle from the positive side of the x-axis is

         θ ’= 180 - θ

        θ ’= 180 - 36.87

        θ ’= 143.13º

       sin143.13 = F_13y / F₁₃

           F_13y = F₁₃ sin 143.13

           F{13y} = 1.697 10⁻² sin 143.13

           F_13y = 1.0183 10⁻² N

            cos 143.13 = F_13x / F₁₃

           F₁₃ₓ = F₁₃ cos 143.13

           F₁₃ₓ = 1.697 10⁻² cos 143.13

           F₁₃ₓ = -1.357 10-2 N

Now we can find the components of the resultant force

          Fx = F13x + F12x

          Fx = -1,357 10-2 +0

          Fx = -1.357 10-2 N

          Fy = F13y + F12y

         Fy = 1.0183 10-2 + ​​1 10-1

          Fy = 0.110183 N

We use the Pythagorean theorem to find the modulus

         F = Ra (Fx2 + Fy2)

         F = RA [(1.357 10-2) 2 + 0.110183 2]

         F = 0.111015 N

Let's use trigonometry for the angles

         tan tea = Fy / Fx

          tea = tan-1 (0.110183 / -0.01357)

          tea = 1,448 rad

to find the angle about the positive side of the + x axis

           tea '= pi - 1,448

           Tea = 1.6936 rad

6 0
3 years ago
How do observing and inferring differ?
Illusion [34]
Observing is commenting on what you see e.g: It is raining.
Inferring is drawing conclusions from observations for example you see the road is wet so you might infer that it rained last night.
6 0
3 years ago
Read 2 more answers
7. How much thermal energy is absorbed when 10.0 g of ice at 0.0 degrees C changes phase to liquid water at 0.0 degrees C? The m
Nesterboy [21]

Answer:

3.34 kJ

Explanation:

FIrst of all, we need to calculate the number of moles corresponding to 10.0g of ice. This is given by

n=\frac{m }{M_m}

where

M_m = 18.02 g/mol is the molar mas

m = 10.0 g is the mass

Substituting

n=\frac{m}{M_m}=\frac{10 g}{18.02 g/mol}=0.555 mol

Now we know that the heat of fusion is

H_{fus}=6.01 kJ/mol

so the thermal energy needed to fuse the ice is

Q=n H_{fus} = (0.555 mol)(6.01 kJ/mol)=3.34 kJ

6 0
3 years ago
Work functions of tungsten and sodium are 4.4 eV and 2.3 eV respectively. If threshold
KonstantinChe [14]

Answer:

(d) 2840 A

Explanation:

Threshold frequency can be be calculated using expresion below

(λ)= hc/ Φ

(λ) sodium/ (λ)tungsten = Φtungsten/ Φsodium

But (λ) sodium is given as 5460 A,

Φsodium = 2.3 eV

Φtungsten= 4.4 eV

If we substitute the values we can find

(λ)tungsten.

(λ)tungsten= [(λ) sodium × Φsodium]/ Φtungsten

=( 5460× 2.3)/4.4

= 2854A

Hence, threshold wavelength of tungsten is 2854A

5 0
3 years ago
How far can a person travel in 19 minutes, walking at a speed of 5.0 km/h ?​
anyanavicka [17]

Answer:

5.0 km/h = 5.0 km/60min

speed = distance/time

distance = speed x time = 5.0km/60min x 19min = 1.6km

Explanation:

4 0
3 years ago
Read 2 more answers
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