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aalyn [17]
3 years ago
9

A cup of tea at 60°C is sitting on a table in a room whose temperature is 24°C. Choose the best statement concerning heat flow.

Heat will flow from the tea into the air in the room. Heat will flow from the air in the room into the tea. There will be no exchange of heat. Heat will flow both ways in equal amounts.
Physics
2 answers:
GalinKa [24]3 years ago
7 0

Answer:

Heat will flow from the tea into the air of the room

Explanation:

Heat Transfer

ZanzabumX [31]3 years ago
3 0

Answer:

Heat will flow from the tea into the air in the room

Explanation:

The sistem is going to find an equilibrium temperature for both elements.

As we have a small hot mass and a large cold mass, that temperature will be colder than the tea (and hotter than the air, but as the size of a cup is too small for a room, it will be almost equal to 24 Celsius)

Then the heat will 'leave' the tea.

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Period of a 60Hz circuit
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An objest with the mass of 2 kg is accelerated at 4 m/s2. the net force acting on the object is
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From Newton’s 2nd law of motion
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3 years ago
Consult Conceptual Example 9 in preparation for this problem. Interactive LearningWare 6.3 also provides useful background. The
Alex73 [517]

Answer:

11.56066 m/s

Explanation:

m = Mass of person

v = Velocity of person = 13.4 m/s

g = Acceleration due to gravity = 9.81 m/s²

v' = Velocity of the person in the second

The kinetic and potential energy will balance each other at the surface

\dfrac{1}{2}mv^2=mgh\\\Rightarrow h=\dfrac{v^2}{2g}\\\Rightarrow h=\dfrac{13.4^2}{2\times 9.81}\\\Rightarrow h=9.15188\ m

Height of the cliff is 9.15188 m

Let height of the fall be h' = 2.34 m

\dfrac{1}{2}mv'^2+mgh'=mgh\\\Rightarrow v'=\sqrt{2g(h-h')}\\\Rightarrow v'=\sqrt{2\times 9.81(9.15188-2.34)}\\\Rightarrow v'=11.56066\ m/s

The speed of the person is 11.56066 m/s

3 0
3 years ago
How do exons and introns differ?
Norma-Jean [14]
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Are you in K12?
7 0
3 years ago
a trampoline launches a 50kg person 2m into the air. if the springs push with 1960N of force, how much displacement was there in
Lina20 [59]

Answer: 0.5 m

Explanation:

Given

Mass of the person is m=50\ kg

Trampoline launches the person into the air up to height of h=2\ m

Force experience by springs is F=1960\ N

Here, the work done on displacing the springs is equivalent to the Potential energy acquired by the person i.e.

\Rightarrow F\cdot x=mgh\quad [\text{x=displacement of the trampoline}]\\\\\text{Insert the values}\\\\\Rightarrow x=\dfrac{50\times 9.8\times 2}{1960}\\\\\Rightarrow x=\dfrac{980}{1960}\\\\\Rightarrow x=0.5\ m

6 0
3 years ago
Read 2 more answers
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