In CONVECTION, heat energy is carried by the movement of particles of matter. In CONDUCTION, heat is transferred by particles vibrating. In RADIATION, heat is carried directly by electromagnetic waves. When a hot object touches a cool object, heat moves from the hot one to the cool one.
The answer is D Transfer of heat through the movement of particles.
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Heres the answer to your question
Answer:
Rubidium (Rb).
Explanation:
From the question given above, the following data were obtained:
Electronic configuration => 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s¹
Name of element =?
To know the name of the element with the above electronic configuration, we shall determine the atomic number of the element. This can be obtained as follow:
Number of electrons = 2 + 2 + 6 + 2 + 6 + 2 + 10 + 6 + 1
Number of electrons = 37
Next, we shall determine the number of protons. This can be obtained as follow:
From the question given above, the element has no charge. Hence the element contains equal numbers of protons and electrons.
Number of electrons = 37
Number of protons = number of electrons = 37
Next, we shall determine the atomic number. This can be obtained as follow:
The atomic number of an element is simply defined as the number of protons present in the atom of the element. Thus,
Atomic number = proton number
Proton is = 37
Therefore,
Atomic number = 37
Finally, we shall determine the name of the element by comparing the atomic number of those in the periodic table.
Thus, the element with the above electronic configuration is Rubidium (Rb) since no two elements have the same atomic number
Answer:
Una partícula subatómica es aquella que es más pequeña que el átomo. Puede ser una partícula elemental o una compuesta, a su vez, por otras partículas, como los quarks que componen los protones y los neutrones. ... De esta manera, se han descubierto docenas de partículas subatómicas, y se teorizan cientos de otras más.
Answer:
1100 millimeters
Explanation:
1 mole of isopentyl alcohol = 22.4L = 22.4×1000 mL = 22,400L
0.050 moles of isopentyl alcohol = 0.050 × 22,400mL = 1120mL = 1100mL (to two significant figures)
