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Alex787 [66]
3 years ago
7

Which of these is not a postulate of the kinetic-molecular theory of gases?

Chemistry
1 answer:
marin [14]3 years ago
6 0

a) Gas particles have most of their mass concentrated in the nucleus of the atom.

b) The moving particles undergo perfectly elastic collisions with the walls of the container.

c) The forces of attraction and repulsion between the particles are insignificant.

d) The average kinetic energy of the particles is directly proportional to the absolute temperature.

e) All of the above are postulates of the kinetic molecular theory.

Gas particles have most of their mass concentrated in the nucleus of the atom.

Answer: Option A.

<u>Explanation:</u>

Kinetic Molecular Theory expresses that gas particles are in consistent movement and show flawlessly versatile crashes. Motor Molecular Theory can be utilized to clarify both Charles' and Boyle's Laws. The normal active vitality of an assortment of gas particles is straightforwardly corresponding to total temperature as it were.

The kinetic theory of gases is a significantly critical, however straightforward model of the thermodynamic conduct of gases with which numerous important ideas of thermodynamics were built up.

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Answer:

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Explanation:

Step 1: Data given

The volume of the tank = 124.0 L

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Step 2: Calculate the initial number of moles

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n = (p*V)/(R*T)

⇒with p = the initial pressure = 104.0 atm

⇒with V = the initial volume = 124.0 L

⇒with n = the initial number of moles = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒ with T = the temperature= 297 K

n = (104.0*124.0)/(0.08206*297)

n = 529.14 moles

Step 3: Calculate final number of moles

p*V = n*R*T

n = (p*V)/(R*T)

⇒with p = the initial pressure = 94.0 atm

⇒with V = the initial volume = 124.0 L

⇒with n = the initial number of moles = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒ with T = the temperature= 297 K

n = (94.0*124.0)/(0.08206*297)

n = 478.26 moles

Step 4: Calculate the difference of moles

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A sample of magnesium is burned in oxygen to form magnesium oxide. What mass of oxygen is consumed if 74.62 g magnesium oxide is
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Answer:

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Substituting

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