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Alex787 [66]
3 years ago
7

Which of these is not a postulate of the kinetic-molecular theory of gases?

Chemistry
1 answer:
marin [14]3 years ago
6 0

a) Gas particles have most of their mass concentrated in the nucleus of the atom.

b) The moving particles undergo perfectly elastic collisions with the walls of the container.

c) The forces of attraction and repulsion between the particles are insignificant.

d) The average kinetic energy of the particles is directly proportional to the absolute temperature.

e) All of the above are postulates of the kinetic molecular theory.

Gas particles have most of their mass concentrated in the nucleus of the atom.

Answer: Option A.

<u>Explanation:</u>

Kinetic Molecular Theory expresses that gas particles are in consistent movement and show flawlessly versatile crashes. Motor Molecular Theory can be utilized to clarify both Charles' and Boyle's Laws. The normal active vitality of an assortment of gas particles is straightforwardly corresponding to total temperature as it were.

The kinetic theory of gases is a significantly critical, however straightforward model of the thermodynamic conduct of gases with which numerous important ideas of thermodynamics were built up.

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Ozone decomposes to oxygen according to the equation 2 O3(g) → 3 O2(g). Write the equation that relates the rate expressions for
Roman55 [17]

Answer:

Check explanation.

Explanation:

The rate of reaction can be defined as the speed at which concentration of Reactant(s) is/are being converted into product(s) or it can be defined as the rate at which the concentration of Reactant(s) disappear and the rate at which the product(s) forms.

For instance, in the Example below;

aA + bB-------> cC + dD. Where a,b,c and d are the number of moles of A,B,C and D respectively.

The rate of Reaction can be expressed as; - 1/a d[A]/dt = –1/b d[B]/dt= 1/c d[C]/dt =1/d d[D]/dt.

So, back to the question; we are given the balanced equation of,

===> 2 O3(g) --------> 3 O2(g).

Rate of disappearance of ozone,O3 is:

= -∆[O3]/ ∆t.

= -1/2 [O3]/∆t.

Where t= time and the [O3} is the concentration of ozone,O3.

Note that we have the negative sign because, ozone is been consumed/used up in the reaction.

==> The rate of the formation of oxygen is ;

= ∆[O2]/∆t.

= 1/3 ∆[O2]/∆t.

7 0
3 years ago
A weak acid, ha, has a p������a of 4. 524. If a solution of this acid has a ph of 4. 799 , what percentage of the acid is not io
insens350 [35]

Answer:

highly endothermic

Explanation:

6 0
2 years ago
The best tool to use to locate the boundaries between countries is a(n) _____.
8_murik_8 [283]

The correct answer is (b) political map

The explanation:

when a political map: is different than other types of maps because it focuses on government or administrative boundaries rather than geographical or physical features. Instead of showing viewers what exists in the land, it shows those imaginary lines that serve to separate countries, states, territories, and cities. These maps generally include larger bodies of water, such as oceans, rivers, and lakes, as landmarks.

It was made by man not natural like the others maps.

so this is the correct answer.

8 0
3 years ago
How does a sample of hydrogen at 10 °C compare to a sample of hydrogen at 350 K?
Aleks04 [339]

Answer: -

The hydrogen at 10 °C has slower-moving molecules than the sample at 350 K.

Explanation: -

Temperature of the hydrogen gas first sample = 10 °C.

Temperature in kelvin scale of the first sample = 10 + 273 = 283 K

For the second sample, the temperature is 350 K.

Thus we see the second sample of the hydrogen gas more temperature than the first sample.

We know from the kinetic theory of gases that

The kinetic energy of gas molecules increases with the increase in temperature of the gas. The speed of the movement of gas molecules also increase with the increase in kinetic energy.

So higher the temperature of a gas, more is the kinetic energy and more is the movement speed of the gas molecules.

Thus the hydrogen at 10 °C has slower-moving molecules than the sample at 350 K.

8 0
3 years ago
Read 2 more answers
If a 95.27 mL sample of acetic acid (HC2H3O2) is titrated to the equivalence point with 79.06 mL of 0.113 M KOH, what is the pH
KATRIN_1 [288]

Answer:

8.73

Explanation:

The concentration of acetic acid can be determined as follows:

M_1V_1 = M_2V_2\\(KOH) = (CH_3COOH)

M_{KOH}=0.113 M\\V_{KOH}=79.06 mL

V_{CH_3COOH}=95.27 \\\\M_{CH_3COOH)=?????

M_{CH3COOH} = \frac{M_{KOH}*V_{KOH}}{V_{CH_3COOH}}

M_{CH3COOH} = \frac{0.113*79.06}{95.27}

M_{CH3COOH} = 0.094 M

Moles of CH_3COOH = 95.27* 10^{-3}* 0.094

=0.0090 moles

Moles of  KOH = 79.06*10^{-3}*0.113

= 0.0090 moles

The equation for the reaction can be expressed as :

CH_3COOH     +      KOH     ----->      CH_3COO^{-}K^+      +     H_2O

Concentration of CH_3COO^{- ion = \frac{0.0090}{Total volume (L)}

= \frac{0.0090}{(95.27+79.06)} *1000

= 0.052 M

Hydrolysis of  CH_3COO^{- ion:

CH_3COO^{-      +       H_2O      ----->      CH_3COOH       +     OH^-

K = \frac{K_w}{K_a} = \frac{x*x}{0.052-x}

⇒    \frac{10^{-14}}{1.82*10^{-5}}= \frac{x*x}{0.052-x}

=     0.5494*10^{-9}= \frac{x*x}{0.052-x}

As K is so less, then x appears to be a very infinitesimal small number

0.052-x ≅ x

0.5494*10^{-9}= \frac{x^2}{0.052}

x^2 = 0.5494*10^{-9}*0.052

x^2 = 0.286*10^{-10

x = \sqrt{0.286*10^{-10

x =0.535*10^{-5}M

[OH] = x =0.535*10^{-5}

pOH = -log[OH^-]

pOH = -log[0.535*10^{-5}]

pOH = 5.27

pH = 14 - pOH

pH = 14 - 5.27

pH = 8.73

Hence, the pH of the titration mixture = 8.73

8 0
3 years ago
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