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First definition matches with expression, second matches with equation ,third matches with algorithm and fourth matches with equation.
Given four definitions of equation, expression, algorithm but mixed.
We have to match the definitions with appropriate term.
We know that expression is a combination of numbers, symbols, fraction, coefficients, indeterminants mostly not found in equal to form. It exhibits a behaviour only.
Algorithm is a computer programming to do a specific task in a predetermined way.
Equation is a relationship between two variables expressed in equal to form. In this we have to put the value of variables and the equation gives us a value.
Hence First definition matches with expression, second matches with equation ,third matches with algorithm and fourth matches with equation.
Learn more about algorithm at brainly.com/question/13800096
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Answer:
Bob bought 5 Adult tickets and 3 Child
Step-by-step explanation:
5 adult tickets = 50$
3 Child tickets= 9$
50$+9$= 59$
Answer:
shirt = $20
sweater = $35
Step-by-step explanation:
This question would be solved using simultaneous equation
Let the price of sweater be represented by a
Let the price of shirt be represented by b
The following equations can be derived from the question
2a + 4b = 150 equation 1
4a + 3b = 200 equation 2
Multiply equation 1 by 2
4a + 8b = 300 equation 3
Subtract equation 2 from 3
5b = 100
divide both sides of the equation by 5
b = 20
substitute for b in equation 1
2a + 4(20) = 150
2a + 80 = 150
collect like terms
2a = 150 - 80
2a = 70
divide both sides by 2
a = 35
Price of sweater = $35
Price of shirt = $20
Formula of the Volume of a hemisphere:
V =
r³
144
=
r³
Multiply by 3 to cancel fraction in the right side
144
× 3 = 2
r³
432
= 2
r³
Divide by 2
on either sides to isolate r³
=
r³
2
and
cancel out
216 = r³
Take cube root to find the radius
![\sqrt[3]{216}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%7D%20)
=
![\sqrt[3]{r^3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Br%5E3%7D%20)
6 = r
Radius is 6 unitsThe formula of the surface area of a hemisphere is:
S.A = 2
r² +
r²
=
(6)² +
(6)²
=2
× 36 + 36
= 72
+ 36
= 108
units² (in terms of
)
≈ 339.12 units²
Surface area = 108 units
