Answer:
x^2+y^2-32x+24y+375=0
Step-by-step explanation:
Equation of circle with given centre (h,k) and radius=r is
(x-h)^2+(y-k)^2=r^2
Given centre are=(16, - 12) and radius= 5
So equation of circle=
(x-16)^2+(y- -12)^2=5^2
x^2-32x+256+y^2+24y+144=25
x^2+y^2-32x+24y+375=0
Answer
Answer:0.05168986083
Step-by-step explanation:
Answer:
y=1 and x = 2
Step-by-step explanation:
Given equations are :
2x-2y = 2 ....(1)
5x+2y= 12 .....(2)
Adding equation (1) and (2),
2x+5x = 2+12
7x = 14
x = 2
Put the value of x in equation (!).
2(2)-2y = 2
4-2y=2
2=2y
y=1
So, the values of x and y are 2 and 1 respectively.
Answer:
No solutions
Step-by-step explanation:
Let's solve your equation step-by-step.
5(3x+5)=3(5x+1)
Step 1: Simplify both sides of the equation.
5(3x+5)=3(5x+1)
(5)(3x)+(5)(5)=(3)(5x)+(3)(1)(Distribute)
15x+25=15x+3
Step 2: Subtract 15x from both sides.
15x+25−15x=15x+3−15x
25=3
Step 3: Subtract 25 from both sides.
25−25=3−25
0=−22
Answer:
There are no solutions.
