Sec(theta) = 1 / cos (theta) = hypotenuse / x -coordinate
hypotenuse = 1 (because it is the radius of the unit circle)
sec (theta) = 1 / (-3/5) = - 5/3
cot (theta) = 1 / tan(theta) = x-coordinate / y - coordinate
cot (theta) = -3/5 / y
y^2 + (-3/5)^2 = 1 => y^2 = 1 - 9/25 = 16/25 = y = +/- 4/5
Third quadrant => y = -4/5
=> cot (theta) = (-3/5) / (-4/5) = 3/4
<span> The product of two perfect squares is a perfect square.
Proof of Existence:
Suppose a = 2^2 , b = 3^2 [ We have to show that the product of a and b is a perfect square.] then
c^2 = (a^2) (b^2)
= (2^2) (3^2)
= (4)9
= 36
and 36 is a perfect square of 6. This is to be shown and this completes the proof</span>
I am not 100% positive.
10 teams play every other ( = 5) once
10 x 5 = 50 games total
Answer:
<h3>20.6 ft</h3>
Step-by-step explanation:
You must use the trigonometric function.
In this case, it will be tangent.
We have
Substitute:
<em>multiply both sides by 20</em>
Tree height is r + 5.
Therefore
9514 1404 393
Answer:
11
Step-by-step explanation:
4 × (2 3/4) = 4×2 + 4×(3/4) = 8 + 3 = 11
or
4 × (2 3/4) = 4 × 11/4 = 11
