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Angelina_Jolie [31]
3 years ago
11

X^3+x^2+x+1 ÷x-1/2 find the remainder

Mathematics
1 answer:
dalvyx [7]3 years ago
3 0

Answer:

Hello,

remainder is 15/8

Step-by-step explanation:

\begin{array}{c|ccc|c}&x^3&x^2&x&1\\---&---&---&---&---\\&1&1&1&1\\x=\dfrac{1}{2} &&\dfrac{1}{2} &\dfrac{3}{4} &\dfrac{7}{8} \\---&---&---&---&---\\&1&\dfrac{3}{2}&\dfrac{7}{4}&\dfrac{15}{8}\\\end{array}\\\\\\x^3+x^2+x+1=(x-\dfrac{1}{2} )*(x^2+\dfrac{3}{2}x+\dfrac{7}{4}) +\dfrac{15}{8}

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