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madam [21]
3 years ago
11

HELP PLS ILL GIVE BRAINLIEST ANSWER HELP ASAP!!

Mathematics
1 answer:
AlexFokin [52]3 years ago
5 0
The answer is C

Hope this helped:)
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1 2 3 4 5 6 7 8 9 10
Maslowich

The graph that represents viable values for y = 2x is Option A.

<h3>What is a Straight Line Function ?</h3>

A straight line function is given by y = mx +c , where m is the slope and c is the y intercept.

The given equation is y = 2x

here m  = 2

x is the number of pounds of rice scooped and purchased from a bulk bin

y is the total cost of the rice

as both the data cannot be negative , Option C , D is out of choice

The Option 1 represents a straight line and it starts at the origin which is satisfied by y = 2x as y = 0 , at x = 0

ends at  point (2.5, 5) giving a slope of m =2 ,

Therefore , The graph that represents viable values for y = 2x is Option A.

To know more about Straight Line equation

brainly.com/question/959487

#SPJ1

6 0
2 years ago
Solve the equation and enter the value of x below.<br> x + 29 = 49<br> X =
andrew-mc [135]

Answer:

x = 20

Step-by-step explanation:

x + 29 = 49

- 29       - 29

x=20

5 0
2 years ago
What's equivlent to 60/1
AnnyKZ [126]

Answer:

60

Step-by-step explanation:

4 0
2 years ago
Which set of numbers does -5 belong ​
tester [92]
Is there any more to this question? Because-5 doesn’t belong anywhere
3 0
2 years ago
A positive integer from one to six is to be chosen by casting a die. Thus the elements c of the sample space C are 1, 2, 3, 4, 5
Alex_Xolod [135]

Answer with Step-by-step explanation:

We are given that six integers 1,2,3,4,5 and 6.

We are given that sample space

C={1,2,3,4,5,6}

Probability of each element=\frac{1}{6}

We have to find that P(C_1),P(C_2),P(C_1\cap C_2) \;and\; P(C_1\cup C_2)

Total number of elements=6

C_1={1,2,3,4}

Number of elements in C_1=4

P(E)=\frac{number\;of\;favorable \;cases}{Total;number \;of\;cases}

Using the formula

P(C_1)=\frac{4}{6}=\frac{2}{3}

C_2={3,4,5,6}

Number of elements in C_2=4

P(C_2)=\frac{4}{6}=\frac{2}{3}

C_1\cap C_2={3,4}

Number of elements in (C_1\cap C_2)=2

P(C_1\cap C_2)=\frac{2}{6}=\frac{1}{3}

C_1\cup C_2={1,2,3,4,5,6}

P(C_1\cup C_2)=\frac{6}{6}=1

4 0
3 years ago
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