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Kobotan [32]
3 years ago
8

Isosceles triangle ABC contains angle bisectors BF. AD and CE that intersect at X

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
3 0

Answer:

the answer is 136°........

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(-5-2)x(-3) what is the answer​
fenix001 [56]

Answer:

21

Step-by-step explanation:

-5 - 2= -7

-7*-3=

<h2>21</h2>
7 0
3 years ago
Read 2 more answers
What is the answer to the question. Solve for x
slega [8]

Answer:

Answer:

x=\frac{75}2

Step-by-step explanation:

Give letters, as in the attached image.

The triangles ABE and CDE are similars (AAA). In particular AE:CE=BE:DE \rightarrow 46:30=(x+20):x \rightarrow 46x=30(x+20) \rightarrow 23x=15x+300 \rightarrow 8x=300\rightarrow  x=\frac{75}2

5 0
2 years ago
Need help help on this question
balu736 [363]

Answer:70

Step-by-step explanation:

step 1:add up the angles you know

step 2:subtract the answer (220) from the total angle measure of a square which is 360 then you get 140

step 3: divide 140 by 2 because the two angles on the sides are equivalent and you get 70

6 0
3 years ago
Point Q'Q ′ Q, prime is the image of Q(0,6)Q(0,6)Q, left parenthesis, 0, comma, 6, right parenthesis under the translation (x,y)
Marina86 [1]

Q is located at (0,6)

The translation rule is (x,y) \to (x+7,y-5) which says to add 7 to the x coordinate and subtract 5 from the y coordinate. Doing that to (0,6) moves it to (7,1) which is where point Q' is located.

In other words, if you shift point Q(0,6) seven units to the right and five units down, then it arrives at Q ' (7,1)

<h3>Answer: (7, 1)</h3>

8 0
3 years ago
The slope f′(x) at each point (x,y) on a curve y=f(x) is given, along with a point (a,b) on the curve. Use this information to f
Montano1993 [528]

f'(x)=\dfrac{4x}{1+7x^2}

Integrating gives

f(x)=\displaystyle\int\frac{4x}{1+7x^2}\,\mathrm dx

To compute the integral, substitute u=1+7x^2, so that \frac27\,\mathrm du=4x\,\mathrm dx. Then

f(x)=\displaystyle\frac27\int\frac{\mathrm du}u=\frac27\ln|u|+C

Since u=1+7x^2>0 for all x, we can drop the absolute value, so we end up with

f(x)=\dfrac27\ln(1+7x^2)+C

Given that f(0)=10, we have

10=\dfrac27\ln1+C\implies C=10

so that

\boxed{f(x)=\dfrac27\ln(1+7x^2)+10}

7 0
3 years ago
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