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nikdorinn [45]
3 years ago
15

PLEASE HELP FAST! MULTIPLE CHOICE! I HAVE 3 MINUTES! PLEASE SHOW A LITTLE WORK I DONT NEED MUCH!

Mathematics
1 answer:
Ksivusya [100]3 years ago
4 0

Answer:

B

Step-by-step explanation:

just multiply 8.50 times 4 and all the numbers in the problem

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The perimeter of a pool is 96 feet. If the length of the pool is 3 times its width, what is the width of the pool? Labeling the
k0ka [10]

Answer:

12 feets

Step-by-step explanation:

Let the area of the pool be Length×width

There will be 2lengths and 2widths as well so the perimeter of the pool will be the addition of all the sides of the pool i.e 2L + 2W = 96... (1)

And since the length of the pool is 3 times its width, we have

L = 3W... (2)

Substituting equation 2 into 1 to get the width 'W'

2(3W) + 2W = 96

6W + 2W = 96

8W = 96

W = 96/8

W = 12feets

The width of the pool is 12feets

4 0
3 years ago
Michael cycled a distance of 12 5/6 miles in 2/3 hours. What is his cycling unit rate in miles per hour?
Annette [7]
19 1/2 miles per hour
4 0
3 years ago
4^3sqrt(3x-3)^2+2=38
vlada-n [284]
Here, 4³√(3x-3)² + 2 = 38

= 4³ (3x - 3) = 38 - 2

= 192x - 192 = 36

= 192x = 192 + 36

= x = 228/192

= x = 1.1875  [ Final Answer ]

Hope this helps!
4 0
3 years ago
The radius of the large sphere is double the radius of the small sphere. How many times is the volume of the large sphere than t
kobusy [5.1K]

The volume of a sphere is \cfrac{4}{3}\ \pi r^3

So, if the small sphere has radius r and the largest sphere has radius 2r, their volumes are

V_1 = \cfrac{4}{3}\ \pi r^3,\quad V_2 = \cfrac{4}{3}\ \pi (2r)^3 = \cfrac{4}{3}\ \pi 8r^3

So, their ratio is

\cfrac{V_2}{V_1} = \cfrac{\frac{4}{3}\ \pi 8r^3}{\frac{4}{3}\ \pi r^3} = 8

7 0
3 years ago
Read 2 more answers
Question 2:
Helga [31]

Answer:

15mins

Step-by-step explanation:

Given that he worked out a total of 360mins, and jogged 45mins/day:

Jog \ Time=Total \ Time- Bike \ Time\\=360-(45\times6)\\=90min

Therefore, Allen jogged a total of 90mins in the past one week. To calculate the time jogged each day, we divide the total jog time by number of days jogged:

t_d=Total \Time/(No \of \ Days)\\=90/6\\=15mins

Allen jogged 15mins per day.

6 0
3 years ago
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