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3 years ago

Compute: 3^(log3 16) - 5^(log5 11)

Mathematics

1 answer:

Nataliya [291]3 years ago

3 0

Answer:

I feel bad for you

Step-by-step explanation:

sorry.....

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Only for (a) please!

Bas_tet [7]

Answer:

Efx=2300 may be it would help : )

Step-by-step explanation:

To find that u have to :

mass mid value(x) Number..(f) fx

10-29 19 32 608

30-39 9 38 342

40-49 9 64 576

50-59 9 35 315

60-69 9 22 198

70-99 29 9 . 261

Efx=2300

3 0

3 years ago

Graph the line that passes through the points (-1,7) and (-3,5) and determine

kari74 [83]

Answer:

y = x + 8

Step-by-step explanation:

find slope first:

m = 7-5 / -1-(-3)

m = 2 / 2

m = 1

now find the y-intercept using either ordered pair; plug 'y', 'x', and 'm' into

y = mx + b to solve for 'b'

7 = 1(-1) + b

7 = -1 + b

8 = b

put 'm' and 'b' into slope-intercept equation of a line, y = mx + b to get:

y = x + 8

5 0

3 years ago

I need help with 5,6,7 please

AlladinOne [14]

Answer:

see explanation

Step-by-step explanation:

the arc length of a circle is calculated as

arc = circumference of circle × fraction of circle

(5)

circumference (C) is calculated as

C = 2πr ( r is the radius )

here diameter = 12 , then r = 12 ÷ 2 = 6

C = 2π × 6 = 12π ≈ 37.7 m ( to the nearest tenth )

(6)

JK = 2πr × $\frac{75}{360}$

= 2π × 7 × $\frac{5}{24}$

= 14π × $\frac{5}{24}$

= $\frac{14\pi (5)}{24}$ ≈ 9.2 in ( to the nearest tenth )

(7)

7.5 = 2πr × $\frac{120}{360}$

7.5 = 2πr × $\frac{1}{3}$ ( multiply both sides by 3 to clear the fraction )

22.5 = 2πr ( divide both sides by 2π )

r = $\frac{22.5}{2\pi }$ ≈ 3.6 ft

7 0

2 years ago

Find the solution to the system of equations

zavuch27 [327]

answer to the question: b

6 0

3 years ago

Consider the function on the interval (0, 2π). f(x) = 7 sin2(x) + 7 sin(x) (a) Find the open interval(s) on which the function i

-BARSIC- [3]

Answer with Step-by-step explanation:

Given

$f(x)=7sin(2x)+7sin(x)$

Differentiating both sides by 'x' we get

$14cos(2x)+7cos(x)=f'(x)$

Now we know that for an increasing function we have

$f'(x)>0\\\\14cos(2x)+7cos(x)>0\\\\2cos(2x)+cos(x)>0\\\\2(2cos^{2}(x)-1)+cos(x)>0\\\\4cos^{2}(x)+cos(x)-2>0\\\\(2cos(x)+\frac{1}{2})^2-2-\frac{1}{4}>0\\\\(2cos(x)+\frac{1}{2})^2>\frac{9}{4}\\\\2cos(x)>\frac{3}{2}-\frac{1}{2}\\\\\therefore cos(x)>\frac{1}{4}\\\\\therefore x=[0,cos^{-1}(1/4)]\cup [2\pi-cos^{-1}(1/4),2\pi ]$

Similarly for decreasing function we have

$[tex]f'(x)$

Part b)

To find the extreme points we equate the derivative with 0

$f'(x)=0\\\\cos(x)=\frac{1}{4}\\\\x=cos^{-1}(\frac{1}{4})$

Thus point of extrema is only 1.

4 0

4 years ago