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pychu [463]
3 years ago
15

Jakie mad 6 quarts of lemonade. Jackie says that she made 3 pints of lemonade. Exspain her error

Mathematics
2 answers:
Contact [7]3 years ago
7 0
We know that 2 pints = 1 quart. So that means that 3 pints = 1 1/2 quarts 
The correct answer would be she made 12 pints because 2 pints = 1 quart
Hope this helped!
frozen [14]3 years ago
6 0
Isn't it 8 quarts for a pint? I'm pretty sure it is.
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What is the value of X?
ladessa [460]
To find the answer make 25 equal to 6x+1
25=6x+1
25-1=24
24=6x
24/6=4
x=4

X=4


4 0
3 years ago
The area of a square is defined by, A(x) = x 2 - 6x + 9. What is the length of a side of the square?
Dmitriy789 [7]
A9x)  = x^2 - 6x + 9  = (x - 3)^2

length of a side = x - 3 
8 0
3 years ago
In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
(5 + 4 - 2) x (-2) = ? <br> A. -22<br> B. 22 <br> C. 14 <br> D. -15
brilliants [131]

It would actually be -14 because 5+4-2=7 and if you multiply 7 by -2 you get -14

4 0
3 years ago
Read 2 more answers
What fractions are greater than 11/20<br><br> a- 3/4<br> b - 3/10<br> c - 4/5<br> d - 1/2
SOVA2 [1]

Answer:

3/4  and  4/5

I hope this helps :)

4 0
3 years ago
Read 2 more answers
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