It is 2 :)
Y=A sin(B(x+C))+D
Where A is equal to the amplitude.
Would appreciate brainliest answer :)
We are to form the combination of 6 objects taken 2 at a time. This can be expressed as 6C2
This means, there can be 15 different combinations of 2 members that can sit in the front row.
So, the answer to this question is option A
Answer: The price of each small box is $4.8 and the price of each large box is $10.8.
Step-by-step explanation:
Let x = Price of each small box, y= price of each large box.
As per given,
3x+2y= 36 ...(i)
4x+y= 30 ...(ii)
Multiplying 2 to (ii), we get
8x+2y =60...(iii)
Subtract (i) from (iii), we get
5x= 24
x= 4.8
From (ii)
4(4.8)+y= 30
19.2+y=30
y= 10.8
Hence, the price of each small box is $4.8 and the price of each large box is $10.8.
|DF| = |DE| + |EF|
|DF| = 9x -36
|DE| = 47
|EF| = 3x+10
Substitute:
9x - 39 = 47 + 3x + 10
9x - 39 = 3x + 57 |+39
9x = 3x + 96 |-3x
6x = 96 |:6
x = 16
Put the value of x to the equation |EF| = 3x + 10
|EF| = (3)(16) + 10 = 48 + 10 = 58
Answer: |EF| = 58
<span>So the question is what are three equivalent ratios for 4/3, 12/14 and 6/9. The simplest way to get the equivalent ratio of some other ratio is to either multiply the nominator and the denominator by the same number or to divide the nominator and the denominator with the same number. I need to point out that it's not always possible to divide them and get a whole number. First: (4/3)*(2/2)=8/6, (4/3)*(3/3)=12/9 and (4/3)*(4/4)=16/12. Second: (12/14)/(2/2)=6/7, (12/14)*(2/2)=24/28 and (12/14)*(3/3)=36/42. Third: (6/9)/(3/3)=2/3, (6/9)*(2/2)=12/18 and finally (6/9)*(3/3)=18/27.</span>
