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DanielleElmas [232]
3 years ago
9

Help pls fast ok ty yh

Mathematics
1 answer:
Neporo4naja [7]3 years ago
7 0

Answer:

the first circle 75

Step-by-step explanation:

hope it helps

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HELP PLEASE! Thank you!
Nataly [62]

Answer:

See attached graph for the first part

Answer to second part: The end part of the graph show the slowest increase

Step-by-step explanation:

The attached picture represents the number of infected people, starting with a relatively small number at the origin of the horizontal axis (x=0, or time=0) then increasing abruptly in the center of the graph with steep slope. and then infection slowing down (although still slowly increasing) in the region highlighted in yellow to the right of the graph.

8 0
3 years ago
Each person eats 2/3 of a pound of turkey. how many pounds of turkey will be needed for 8 people
dezoksy [38]
Multiply 2/3 by 8 and you will get 16/3 or 5.33 repeating.
4 0
3 years ago
Read 2 more answers
Consider the equation 1+n+6/n+1=4/n-2
Inga [223]
A. The LCD is (n+1)(n-2)

B. n = -1, n = 2

C. n = negative 1 plus or minus the square root of 73, everything divided 2.

I’ve add a picture of the answers at the bottom in case I wasn’t clear on question C.

Hope that helps.

8 0
4 years ago
Read 2 more answers
Ask your teacher find the limit. use l'hospital's rule where appropriate. if there is a more elementary method, consider using i
liberstina [14]

Answer:

  ln(5/3)

Step-by-step explanation:

The desired limit represents the logarithm of an indeterminate form, so L'Hopital's rule could be applied. However, the logarithm can be simplified to a form that is not indeterminate.

<h3>Limit</h3>

We can cancel factors of (x-1), which are what make the expression indeterminate at x=1. Then the limit can be evaluated directly by substituting x=1.

  \diplaystyle \lim\limits_{x\to1}{(\ln(x^5-1)-\ln(x^3-1))}=\lim\limits_{x\to1}\ln{\left(\dfrac{x^5-1}{x^3-1}\right)}\\\\=\lim\limits_{x\to1}\ln\left(\dfrac{x^4+x^3+x^2+x+1}{x^2+x+1}\right)=\ln{\dfrac{5}{3}}

8 0
1 year ago
Ray had 60 football cards last year.This year he has 200. Find the percent of change
bulgar [2K]

Answer:70%

Step-by-step explanation: no. of cards last year=60

no. of cards presently=200

increase in no. of cards=200-60

                                        =140

%change=140/200 x 100

7 0
3 years ago
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