Answer:
The answer is option (4) Maximize redundancy as normalization minimizes redundancy of data.
Explanation:
Normalization of databases leads to minimization of data redundancy in databases. It doesn't maximize data redundancy. Data redundancy leads to wastage of resources. Normalization of databases minimizes insertion anomolies. Normalization of databases minimizes deletion anomolies. Normalization of databases minimizes updation anomolies. So , the answer to the question is option (4) maximize redundancy.
Answer:
The reason is due to proprietary design of the Operating System (OS) which require a virtualization software to blanket or "disguise" the hardware (processor) borderlines of the computer onto which it is to be installed.
Explanation:
An Apple system that has the RISC processor and system architecture which has an operating system made entirely for the Apple system architecture
If the above Apple OS is to be installed on a windows computer, then the procedure to setup up the OS has to be the same as that used when on an Apple system, hence, due to the different processors and components of both systems, a virtualization will be be needed to be provided by a Virtual box, Parallels desktop or other virtualization software.
Answer:
beacon frame
Explanation:
Beacon frame is a management frame In computer networks, known to be in IEEE 802.11 based WLANs. These frames are transmitted periodically and they contain all the information a station will require before it can rightly transmit a frame.
When it comes to announcing the presence of devices in a wireless computer network (WLAN), Beacon frames are used, and they can also be used in the synchronization of the devices and services
Moral status because moral status is your feelings
Answer:
Code to the answer is shown in the explanation section
Explanation:
import java.util.Scanner;
public class Question {
public static void main(String args[]) {
Scanner scan = new Scanner(System.in);
System.out.println("Please enter the days of the month: ");
int daysOfMonth = scan.nextInt();
int minuteOfMonth = daysOfMonth * 60 * 24;
System.out.println(minuteOfMonth);
}
}
// 60 represents the number of minutes in one hour
// 24 represents the number of hours in a day
