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ElenaW [278]
3 years ago
8

Select the values that make the inequality true.

Mathematics
1 answer:
Sladkaya [172]3 years ago
6 0

Answer: 35,40,45,50,55

That is the answer to the 1st part.

Step-by-step explanation:

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What is the solution to the equation 5 (x minus 6) = 2 (x + 3)?
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Answer:

x=12

Step-by-step explanation:

5(x-6)=2(x+3)

5x-30=2x+6

5x=2x+36

3x=36

x=12

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Suppose that the functions u and w are defined as follows.
jasenka [17]

Answer(there are assumptions for this answer that you need to confirm and look at):

Assumptions: u(x)=x^2+3 and w(x)=\sqrt{x+2}

Answer if the operation is multiplication:

If you meant a closed dot which is the symbol for multiplication.

(u \cdot w)(2)=14

(w \cdot u)(2)=14

Answer if the operation is composition:

If you meant an open dot which is the symbol for composition.

(u \circ w)(2)=7

(w \circ u)(2)=3

Note: I don't know if you actually meant w(x)=\sqrt{x+2} or if w(x)=\sqrt{x}+2. Please let me know one way or the other.

Step-by-step explanation:

If we assume the functions are:

u(x)=x^2+3

w(x)=\sqrt{x+2}

u \cdot w=w \cdot u since multiplication is commutative.

u(2)=2^2+3

u(2)=4+3

u(2)=7

w(2)=\sqrt{2+2}

w(2)=\sqrt{4}

w(2)=2

We are asked to find (u \cdot w)(2) and (w \cdot u)(2).

The order doesn't matter in multiplication.

(u \cdot w)(2)

u(2) \cdot w(2)

7 \cdot 2

14

(w \cdot u)(2)

w(2) \cdot u(2)

2 \cdot 7

14

Now you might have meant composition which symbolized with an open circle, not a closed one.

(u \circ w)(2)

u(w(2))

u(2) since w(2)=2

2^2+3

4+3

7

(w \circ u)(2)

w(u(2))

w(7) since u(2)=7

\sqrt{7+2}

\sqrt{9}

3

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Your teacher gives you a graph of the parent function y = x^2 and the graph of another function. You notice that the new functio
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It’s either B or C if it’s being translated to the right it’s B but if it’s being translated to the left it’s C
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