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dybincka [34]
2 years ago
7

HELP ASAP!!!20pts 1/3x=−20 WHAT IS X?

Mathematics
2 answers:
zmey [24]2 years ago
7 0

Answer:

x = -60

Step-by-step explanation:

1/3x=−20

X is 1/3

X times 3 = a full X

Fill it in

X times -20 = -60

Hope this helps :)

s2008m [1.1K]2 years ago
6 0
X = -60

Hopes this helps
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How many zeros in the standard form of 10/3
Slav-nsk [51]

If you meant, "how many zeros are there in the standard form of 'ten divided by 3,' the answer would be, "none."


10/3 = 3.3333333333333.... This is a repeating decimal.


7 0
3 years ago
Earth has a radius of about 6400 km, the sun has a radius of about 7.0´105 km, and a rubber ball has a radius of 6.4 cm. if you
tresset_1 [31]
<span>700 cm
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4 0
3 years ago
Do Now: Find the area, 15 cm 13 cm 112 cm 5 cm 9 cm IN A TRIANGLE​
Lilit [14]

Answer:

triangle is a polygon which has three sides and can be categorized into the follow types:

·         An equilateral triangle has equal sides and equal angles.

·         An isosceles triangle has two equal sides and two equal angles.

·         A scalene triangle has three unequal sides and three unequal angles.

·         A right-angled triangle has one right angle (90°).

·         An acute-angled triangle has all angles less than 90°.

·         An obtuse-angled triangle has one angle greater than 90°.



The perimeter of a triangle = Sum of three sides

In the figure alongside of the ΔABC, the perimeter is the sum of AB + BC + AC.

 

Area of a triangle is given by:

A = ½ × Base × Height

Any side of the triangle may be considered as its base.

Then, the length of the perpendicular line from the opposite vertex is taken as the corresponding height or altitude.

In the figure shown above the area is thus given as: ½ × AC × BD.

 

Additional formulas for determining the area of a triangle:

Area of a triangle = √(s(s-a)(s-b)(s-c)) by Heron's Formula (or Hero's Formula), where a, b and c are the lengths of the sides of the triangle, and s = ½ (a + b + c) is the semi-perimeter of the triangle.

 

Area of an equilateral triangle

A= √(3) · ¼ · side, where side = a = b = c

 

Area of an isosceles triangle

A = ¼ ·b · √(4a2 – b2)

 

Area of the right angled triangle

A= ½× Product of the sides containing the right angle.

 

If two sides and the angle between them are given then the area of the triangle can be determined using the following formula:

Area = ½ · a · b · sinC = ½ · b · c · sinA = ½ · a · c · sin B

 

 

Example 1: Find the area of a triangle whose base is 14 cm and height is 10 cm.

Solution:

b = 14 cm

h = 10 cm

A = ½ · 14 · 10 = 70 cm2

 

 

Example 2: Find the area of a triangle whose sides and the angle between them are given as following:

a = 5cm and b = 7cm

C = 45o

Solution:

Area of a triangle = ½ · a · b · sinC

Area = ½ × 5 ×7 × 0.707 (since sin 45 ° = 0.707)

Area = ½ × 24.745 = 12.3725 m2

 

 

Example 3: Find the area (in m2) of an isosceles triangle, whose sides are 10 m and the base is12 m.

Solution:

The area of an isosceles triangle is determined by:

 

A = ¼ ·b · √(4a2 – b2)

A = ¼ ·12 · √(4(10)2 – (12)2)

A = 48 m2

 

 

 

Example 4: Find the area of a triangle whose sides are 8, 9 and 11 respectively. All units are measured in meter (m).

Solution:

Given: sides a = 8, b = 9 and c = 11

According to Heron’s Formula the area of a triangle can be determined using the following formula:

A = √(s(s-a)(s-b)(s-c))

 

First of all, we need to determine the s, which is the semi-perimeter of the triangle:

s = ½ (a + b + c) = ½ (8 + 9 + 11) = 14

 

Now by inserting the value of the semi-perimeter into the Heron’s formula we can determine the area of the triangle:

 

A = √(s · (s-a) · (s-b) · (s-c))

A = √(14 · (14-8) · (14-9) · (14-11))

A = √(1260 ) = 35.50 m2

 

 

Example 5: Farmer Munnabhai owns a triangular piece of land. The length of the fence AB is 150 m. The length of the fence BC is 231 m. The angle between fence AB and fence BC is 123º.

How much land does Farmer Munnabhai own?

Solution: First of all we must decide which lengths and angles we know:



AB = c = 150 m

BC = a = 231 m

and angle B = 123º

 

To determine the area of the land, we can use the following formula:

 

Area = ½ · c · a · sin B

Area = ½ ×150 × 231 × sin(123º )

Area = 17,325 ×0.8386

Area = 14,529 m2

 

Therefore, farmer Munnabhai has 14,529 m2 of land.

6 0
3 years ago
What does it mean when the numbers are on the button side of the whole numbers
Tomtit [17]

Answer:

what do you mean on the button side??

Step-by-step explanation:

7 0
3 years ago
A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 49.049.0 and
sveta [45]

Answer:

10% probability that a given class period runs between 51.25 and 51.75 minutes.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability of finding a value X between c and d, d greater than c, is given by the following formula:

P(c \leq X \leq d) = \frac{d-c}{b-a}

Uniformly distributed between 49 and 54 minutes

This means that b = 54, a = 49

Find the probability that a given class period runs between 51.25 and 51.75 minutes.

P(51.25 \leq X \leq 51.75) = \frac{51.75 - 51.25}{54 - 49} = 0.1

10% probability that a given class period runs between 51.25 and 51.75 minutes.

6 0
3 years ago
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