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masya89 [10]
2 years ago
13

(03.01 LC)

Mathematics
2 answers:
vampirchik [111]2 years ago
4 0

Answer:

√7 units, √98 units

Step-by-step explanation:

Pythagorean theorem

a^2+b^2=c^2. So 9+b^2=16. So b^2=7. So b=√7

a^2+b^2=c^2. SO 49+49=c^2. So 98=c^2. So c=√98.

Evgesh-ka [11]2 years ago
4 0

Answer:

√7 units, √98 units

Step-by-step explanation:

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hram777 [196]
I can't see the math problems.
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3 years ago
Please help me with this<br> simplify sqrt24w^14
Serjik [45]

Answer:

2×sqrt(6)×w⁷

Step-by-step explanation:

what I can read here, you need to simplify

sqrt(24×w¹⁴)

= sqrt(24)×sqrt(w¹⁴) = sqrt(4×6)×sqrt(w¹⁴) =

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2×sqrt(6)×w⁷

6 0
3 years ago
2(4x – 12) + 10 – 6x = 12
SashulF [63]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Evaluate.<br><br><br> -1<br> (1/5) ⋅ 4^0<br><br><br><br><br> 0<br><br> 1<br><br> 5<br><br> 20
Ierofanga [76]

Answer:

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5 0
2 years ago
Mason walked on Monday, Wensday, and Friday. Use these clues to find how far he walked each day. These distances were six-eights
krok68 [10]

Answer:

Monday he walked \frac{1}{4}miles

Wednesday he walked \frac{6}{8}miles

Friday he walked \frac{1}{6}miles

Step-by-step explanation:

Given Mason walked on Monday, Wednesday and Friday. These distances were six-eights mile, one-fourth mile, and one-sixth mile. He did not walk the farthest on Monday. He walked less on Friday than Monday. we have to find how far he walked each day.

distances are \frac{6}{8}, \frac{1}{4}, \frac{1}{6} that are 0.75, 0.25 and 0.17 respectively.

Now, he didn't walk farthest on Monday and also walked less on Friday than Monday.

∴ Less distance travelled is \frac{1}{6} which is on friday and then \frac{1}{4} on monday.

Rest distance which is \frac{6}{8} on wednesday.

Hence, Monday he walked \frac{1}{4}miles

Wednesday he walked \frac{6}{8}miles

Friday he walked \frac{1}{6}miles

4 0
3 years ago
Read 2 more answers
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