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viva [34]
2 years ago
10

Write the following number in standard form. three and fifteen hundredths 3.15 3.015 315 3.105

Mathematics
1 answer:
soldier1979 [14.2K]2 years ago
3 0
3.105 I believe.. not 100% sure.
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Please help me as soon as posable!! In hurry!!(24 points)
attashe74 [19]

The sequence is geometric, so

a_n = r a_{n-1}

for some constant r. From this rule, it follows that

a_3 = r a_2 \implies 20 = 2r \implies r = 10

and we can determine the first term to be

a_2 = r a_1 \implies 2 = 10 a_1 \implies a_1 = \dfrac15

Now, by substitution we have

a_n = r a_{n-1} = r^2 a_{n-2} = r^3 a_{n-3} = \cdots

and so on down to (D)

a_n = r^{n-1} a_1 = 10^{n-1} \cdot \dfrac15

(notice how the exponent on r and the subscript on a add up to n)

4 0
1 year ago
"Solving Equations by Completing the Square: m^2+2m-48=-6
kvv77 [185]
m^2+2m-48=-6 \\ \\ m^2+2m-48+6=0\\ \\m^2+2m-42=0\\ \\a=1, \ b= 2, \ c= -42 \\ \\\Delta = b^{2}-4ac = 2^{2}-4*1*(-42)= 4+168 =172 \\\\\sqrt{\Delta }=\sqrt{172} =\sqrt{4*43}=2\sqrt{43}\\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-2-2\sqrt{43}}{2}=\frac{2(-1-\sqrt{43})}{2}= -1-\sqrt{43} \\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} = \frac{-2+2\sqrt{43}}{2}=\frac{ 2(-1+\sqrt{43})}{2}= -1+\sqrt{43}
5 0
2 years ago
Read 2 more answers
PLS HELP ME ASAP WITH 11!! (MUST SHOW WORK!!) + LOTS OF POINTS!! *best if u sent picture with work SHOWN!!* - will give brainlie
sammy [17]
She can travel 12 miles
5 0
2 years ago
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A BMW that cost $71,000 in 2003 depreciates in value about 15% a year. How much was it worth in 2013?
N76 [4]
100-15= 85% 

2013-2003= 10 years

$71,000 * (0.85^10yrs)= $13,978<span>.</span>08

Did this make sense or would you like me to explain some more about something you are still not understanding? Please comment below :)
6 0
3 years ago
A gardener is planting two types of trees:
ICE Princess25 [194]

Answer:

After 1 year, both the tress will be of the same height.

Step-by-step explanation:

Let us assume in x years, both trees  have same height.

Type A  is 7 feet tall and grows at a rate of 8 inches per year.

⇒The growth of tree A in x years = x times  ( Height growth each year)

                                                        = 8 (x)  = 8 x

⇒Actual height of tree A in x years  = Initial Height + Growth in x years

                                                             = 7 + 8 x

or, the height of tree A after  x years  = 7 + 8x

Type B is 9 feet tall and grows at a rate of 6 inches per year.

⇒The growth of tree B in x years = x times  ( Height growth each year)

                                                        = 6 (x)  = 6 x

⇒Actual height of tree B in x years  = Initial Height + Growth in x years

                                                             = 9 + 6 x

or, the height of tree B after  x years  = 9 + 6x

According to the question:

After x years, Height of tree A  =Height of tree B

⇒7 + 8x   = 9 + 6x

or, 8x - 6x = 9 - 7

or, 2 x  = 2

or, x  =  2/2  = 1    ⇒ x  = 1

Hence, after 1 year, both the tress will be of the same height.

5 0
2 years ago
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