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The line that passes through (-2, 1) and (8, 2) is:
y = (1/10)*x + 12/10
<h3>How to find the equation of the line?</h3>I assume you want to find the equation of the line that passes through (-2, 1) and (8, 2).
A general linear equation is written as:
y = a*x + b
If the line passes through two points (x₁, y₁) and (x₂, y₂), then the slope can be written as:
In this case, we know that it passes through (-2, 1) and (8, 2), then:
Then the line is:
y = (1/10)*x + b
To find the value of b, we use one of the given points, for example if we use (8, 2), it means that when x = 8, we must have y = 2.
2 = (1/10)*8 + b
2 - 8/10 = b
20/10 - 8/10 = b
12/10 = b
Then the linear equation is:
y = (1/10)*x + 12/10
If you want to learn more about linear equations:
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Answer:
Step-by-step explanation:
Differentiating, you get ...
... x·dy +y·dx +dx +dy = 2x·dx +2y·dy
Collecting terms gives ...
... dy(x +1 -2y) = dx(2x -y -1)
... dy/dx = -(2x -y -1)/(2y -x -1)