<span>The
content of any course depends on where you take it--- even two courses
with the title "real analysis" at different schools can cover different
material (or the same material, but at different levels of depth).
But yeah, generally speaking, "real analysis" and "advanced calculus"
are synonyms. Schools never offer courses with *both* names, and
whichever one they do offer, it is probably a class that covers the
subject matter of calculus, but in a way that emphasizes the logical
structure of the material (in particular, precise definitions and
proofs) over just doing calculation.
My impression is that "advanced calculus" is an "older" name for this
topic, and that "real analysis" is a somewhat "newer" name for the same
topic. At least, most textbooks currently written in this area seem to
have titles with "real analysis" in them, and titles including the
phrase "advanced calculus" are less common. (There are a number of
popular books with "advanced calculus" in the title, but all of the ones
I've seen or used are reprints/updates of books originally written
decades ago.)
There have been similar shifts in other course names. What is mostly
called "complex analysis" now in course titles and textbooks, used to be
called "function theory" (sometimes "analytic function theory" or
"complex function theory"), or "complex variables". You still see some
courses and textbooks with "variables" in the title, but like "advanced
calculus", it seems to be on the way out, and not on the way in. The
trend seems to be toward "complex analysis." hope it helps
</span>
Answer:
It is not a function because both (2,2) and (2,-2) have the same x-coordinate.
Step-by-step explanation:
To be a function for the same x value there should NOT be two different y values.
So, in (2, 2) and (2,-2)
For the same x value 2, there are two different y values 2, -2.
So, this is not a function.
Answer:
c. 6x6
Step-by-step explanation:
because 6x6 is =36
We call x the 4 points-worth problems and y the 3 points-worth problems
You know that x+y = 32
4x+3y = 111
You know that the difference from the x and y is 32 so write:
x = 32-y
Substitute at x the value of 32-y
4(32-y)+3y = 111
128-4y +3y = 111
-4y+3y = 111-128
-y = -17
y = 17
Answer:
y = 10
Step-by-step explanation:
based on the question if y varries directly as x
mathematically
y ∝ x
also, y varries inversly as z can be mathematically expressed as
y ∝ 1/z
combining the two expressions
y ∝ x ∝ 1/z
i. e
y = kx/z..... where k is the constant of proportionality
make k the subject of formulae
yz = kx
Divide both sides by x
k =yz/x
when y=100 , x = 5 z =10
k = 100 × 10/5
k = 200
to find y when x = 3 and z = 60
<h3>from the equation connecting x,y,z</h3>
k =yz/x
200 =60y/3
cross multiply
60y = 200 × 3
60y = 600
divide both sides by 60
y = 10
