Answer:
7.64% probability that they spend less than $160 on back-to-college electronics
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Probability that they spend less than $160 on back-to-college electronics
This is the pvalue of Z when X = 160. So



has a pvalue of 0.0763
7.64% probability that they spend less than $160 on back-to-college electronics
Answer:
5
is the answer dont over think it and try plz bc its very easy
Answer:
As θ increases, the value of cos θ decreases
Step-by-step explanation:
As as θ increases, the value of cos θ decreases from 1 to -1 in the first two quadrants ( between 0 and 180 degrees). Cos(0) = 1, cos(90) = 0, cos(180) = -1.
On the other hand, as θ increases from 180 to 360 degrees (last two quadrants) the value of cos θ increases from -1 to 1.
Check the attachment below:
Step-by-step explanation:
Let's represent the two integers with the variables
and
.
From the problem statement, we can create the following two equations:


With the first equation, we can subtract
from both sides to isolate the
variable to the left-hand side:

Now that we have a value for
, we can plug it into the second equation and solve for
:


Now, let's move everything to one side of the equation:

Factoring this quadratic will give us two values for
:


Since we now know
, we can plug this back into either of the original equations to get a value for
, which will be
.
So the two numbers that sum to
and have a product of
are
.