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2 years ago

12.) What is the area of the triangle in the coordinate plane?

Mathematics

1 answer:

nirvana33 [79]2 years ago

7 0

Answer:

18u most likely

Step-by-step explanation:

the triangle is 6 units wide and half of it (the height) is 6. so 6 x 6 = 36 divided by 2 = 18u

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A line with slope

spayn [35]

Answer:

(0, 8/3) = y-intercept

Step-by-step explanation:

I chose to find the y-intercept since it is easy to find with the given information.

The equation for a line is y = mx + b

To find the y-intercept, we must plug in the info we have and solve for b:

4 = -1/3 (-4) + b

4 = -4/3 + b

8/3 = b

To find a point on the line, you also could have added -1 to 4 and 3 to -4 since slope means rise/run or change in y/change in x:

(y - 1) / (x + 3) = (4 - 1) / (-4 + 3) = (3, -1) (flip since it's the y and x coordinate) = (-1, 3)

6 0

1 year ago

Porfabor necesito ayuda en la esta pregunta. ¿Encuentra cuatro pares ordenados de la siguiente función? f(x) = X3 – 2X2 – 2

zlopas [31]

Answer:

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de $f(x) = x^{3}-2\cdot x^{2}-2$ .

Step-by-step explanation:

Un par ordenado es un elemento de la forma $(x,f(x))$ , donde $x$ es un elemento del dominio de la función, mientras $f(x)$ es la imagen de la función evaluada en $x$ . Entonces, un par ordenado que está contenido en la citada función debe satisfacer la siguiente condición:

La imagen de la función existe para un elemento dado del dominio. Esto es:

$x \rightarrow f(x)$

Dado que $f(x)$ es una función polinómica, existe una imagen para todo elemento $x$ . Ahora, se eligen elementos arbitrarios del dominio para determinar sus imágenes respectivas:

x = 0

$f(0) = 0^{3}-2\cdot (0)^{2}-2$

$f(0) = -2$

(0, -2) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 1

$f(1) = 1^{3}-2\cdot (1)^{2}-2$

$f(1) = -3$

(1, -3) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 2

$f(2) = 2^{3}-2\cdot (2)^{2}-2$

$f(2) = -2$

(2, -2) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 3

$f(3) = 3^{3}-2\cdot (3)^{2}-2$

$f(3) = 7$

(3, 7) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de $f(x) = x^{3}-2\cdot x^{2}-2$ .

6 0

2 years ago

Which ones are the distance formula and midpoint formula?

lutik1710 [3]

Answer:

The distance formula is $d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)2}$

The midpoint formula is $\left(\frac{x_1\:+x_2}{2}\right),\left(\frac{y_1-y_2}{2}\right)$

Step-by-step explanation:

apply the pythagorean theorem on a coordinate grid

7 0

2 years ago

Breyers is a major producer of ice cream and would like to test the hypothesis that the average American consumes more than 17 o

zhenek [66]

Answer:

The p-value would be 0.0939

Step-by-step explanation:

We can set a standard t-test for the Null Hypothesis that $H_0: 18.2\geq 17$

The test statistic then takes the form

$t=\frac{18.2-17}{3.9/\sqrt{15}}=1.317$

with this value we then can calculate the probability that is left to the right of this value $P(X>1.317)$ . From theory we know that t follows a standard normal distribution. Then $P(X>1.317)=0.0939$ which is smaller than the p-value set by Breyers of 0.10

3 0

2 years ago

PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS

ahrayia [7]

Answer:

Step-by-step explanation:

6 0

1 year ago

Read 2 more answers