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s344n2d4d5 [400]
3 years ago
14

PLEASE HELP!! Name the solution to this system of equations:

Mathematics
1 answer:
RoseWind [281]3 years ago
3 0

9514 1404 393

Answer:

  (x, y) = (3, -1)

Step-by-step explanation:

The solution to the system of equations is the point where the lines intersect.

  (x, y) = (3, -1)

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Write an equation that relates the number of peppers, n, and the<br><br> cost, C.
SCORPION-xisa [38]

Complete Question:

The local Farm Market sells peppers at five for $2.25. Write an equation that relates the number of peppers, n, and the  cost, C.

Answer:

C = 0.45n

Step-by-step explanation:

Given

5\ peppers = \$2.25

Required

Determine the relationship between C and n

5\ peppers = \$2.25

Divide both sides by 5, to get the cost of 1 pepper

\frac{5\ peppers}{5} = \frac{\$2.25}{5}

1\ pepper = \frac{\$2.25}{5}

1\ pepper = \$0.45

Multiply both sides by n to get the cost of n pepper

n*1\ pepper = \$0.45*n

n\ pepper = \$0.45n

So, we have:

C = 0.45n

5 0
3 years ago
How can you tell when a pattern shows counting on by tens?
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Counting by Tens with numbers 10, 20, 30, 40, 50, 60, 70, 80, 90 Counting by Tens with words ten, twenty, thirty, forty, fifty, sixty, seventy, eighty, ninety, one hundred Number Patterns when counting by Tens When you count by tens the numbers create a pattern. All the numbers end with a zero. The first digits are just like the numbers when you count (1, 2, 3, 4, 5, etc.). This pattern gives the numbers 10, 20, 30, 40, 50, etc. found from: http://www.aaamath.com/k4c_cox1.htm
8 0
3 years ago
Read 2 more answers
Please answer I’ll rate brainlyest
12345 [234]

Answer:

5P3*6C4=60*15=900

Step-by-step explanation:

5P3 refers to the permutations of 5 items taken 3 at a time. To evaluate this, we use factorials as follows;

5P3=\frac{5!}{(5-3)!}

The factorial of an integer n is evaluated as;

n!=n*(n-1)*(n-2)*(n-3).......3*2*1

Using this concept, the above expression can now be simplified as follows;

5P3=\frac{5!}{2!}=\frac{5*4*3*2!}{2!}=5*4*3=60

Therefore, the permutations of 5 items taken 3 at a time is 60.

The next expression, 6C4 refers to the combinations of 6 items taken 4 at a time. The simplification utilizes similar concepts of permutations since we shall be involving factorials;

6C4=\frac{6!}{4!(6-4)!}=\frac{6!}{4!*2!}=\frac{6*5*4!}{4!*2*1}=\frac{6*5}{2*1}=15

Therefore, the combinations of 6 items taken 4 at a time is 15.

The final step is to evaluate the product;

5P3*6C4=60*15=900

3 0
3 years ago
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