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Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em><em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em><em>, where </em><em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:
(1)
By Quadratic Formula:
,
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Answer:
<h2>
u = 6.88</h2>
Solution,
Sinplify the equation using cross multiplication
Calculate the product
Divide both sides of the equation by 17
Calculate
Hope this helps...
Good luck on your assignment..
Day Sis you
1 -30 20
2 0 40
3 30 60
4 60 80
5 90 100
6 120 120
So day 6.