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Kazeer [188]
3 years ago
8

Solve 7m+2n=21 and 10m+4n=-10 with substitution

Mathematics
1 answer:
schepotkina [342]3 years ago
3 0
I hope this helps you



10m+4n= -10


5m+2n= -5


-5m-2n= 5



7m+2n-5m-2n= 21+5


5m=26 m= 26/5


5.26/5+2n= -5


26+2n= -5


2n= -31


n= -31/2
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Answer:

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Step-by-step explanation:

<u><em>Verify each statement</em></u>

1) The area of the first enlargement is 72 square inches.

The statement is false

Because

we know that

The original dimensions of the rectangle are

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2) The area of the second enlargement is 1,944 square inches

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Length: 18(3)=54\ inches\\Width: 12(3)=36\ inches

The area of the second enlargement is

54(36)=1,944\ in^2

3) The area of the second enlargement is (3 squared) squared times the original area.

The statement is true

Because

The original area is 24 square inches

[(3^2)]^2(24)=1,944\ in^2

4) The area of the second enlargement is 3 times the area of the first enlargement

The statement is false

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3(216)=648\ in^2

so

648\ in^2 \neq 1,944\ in^2

5) The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor

The statement is true

Because

The square of the scale factor is 3^2=9

and the ratio is equal to

\frac{216}{24}=9

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