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2 years ago

What is the perimeter of a sandbox that measures 5 feet by 6 feet?

Mathematics

1 answer:

hjlf2 years ago

6 0

Answer:

22 feet

Step-by-step explanation:

6+5+6+5

= 11+11

= 22

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Hi, a recipe calls for 1/2 cups of flour. How much flour should be used if only half of the recipe is to be made. Thank You.

Luden [163]

Answer:

¼ cup of flour

Step-by-step explanation:

½ of ½ cup = ½×½ cup = ¼ cup

4 0

3 years ago

Read 2 more answers

I need help with number 13 please.

Tanzania [10]

1 and 3 they share a relationship of +2, 3 and 6 share x2, 5 and 8 share +3, 7 and 21 share x3

3 0

3 years ago

A kite is stuck in a 36-ft tree. If the angle of elevation from the kite and the ground is 12, find the length of the kite.

yanalaym [24]

Answer:

173.15 ft.

Step-by-step explanation:

Please find the attachment.

Let L be the length of kite.

We have been given that a kite is stuck in 36-ft tree. The angle of elevation from the kite and the ground is 12.

We can see from our attachment that kite and tree form a right triangle. height of tree is opposite of angle of elevation and length of kite is hypotenuse.

Since we know that Sine relates the opposite and hypotenuse of a right triangle, so we will use sine to find the length of kite.

$sin(12)=\frac{36}{L}$

$L=\frac{36}{sin(12)}$

$L=\frac{36}{0.207911690818}$

$L=173.1504364105882792\approx 173.15$

Therefore, the length of kite is 173.15 ft.

4 0

2 years ago

What is the reminder when (3x^3-2x^2+4x-3) is divided by (x^2+3x+3)

NARA [144]

(For full answer you might have to go to the comments)

Answer: 28x+30

Explanation: we divide (3x^3-2x^2+4x-3) by (x^2+3x+3) Using long division
3x-11
___________________
(x^2+3x+3) 3x^3-2x^2+4x-3

-(3x^3+9x^2+9x)
__________________

-11x^2-5x-3

-(-11x^2-33x-33)
____________
28x+30

So our remainder will be 28x+30

5 0

2 years ago

Lee is thinking of 2 numbers, the product is 18.the quotient is 2. what are yhe two numbers?

jeka94

$xy=18\\
\dfrac{x}{y}=2\\\\
xy=18\\
x=2y\\\\
2y\cdot y=18\\
2y^2=18\\
y^2=9\\
y=-3 \vee y=3\\\\
x=2\cdot (-3) \vee x=2\cdot 3\\
x=-6 \vee x=6\\\\
\boxed{(x,y)=\{(-6,-3),(6,3)\}}$

4 0

3 years ago