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3 years ago

5

Select the qualification that is best demonstrated in each example.

1 answer:

Simora [160]3 years ago

8 0

Answer:

I think your answers are right.

Step-by-step explanation:

hope this helps, have a good day :)

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I forgot someone help me plz

o-na [289]

Write the conjugates of them then FOIL both the top and bottom, then factor

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3 years ago

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Is the height of 6 and the volume of 96 proportional to the height of 4 and the volume of 64

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Answer:

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3 years ago

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5x2/11. how do i find simplest form

adelina 88 [10]

Assuming you are multiplying 5 times 2/11 then you just put 5/1 because anything divided by 1 is still one, and then multiply 5/1 by 2/11. Meaning, 5 times 2 is 10. And 1 times 11 is 11. So it would be 2/11. You multiply the numerators(top number) and denominators(bottom number). 2/11 is already simplified

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4 years ago

How many solutions does y=2x+1 and x=-3 have

Nikolay [14]

Answer:

- 5

Step-by-step explanation:

given,

the relation is y=2x+1

if x=-3 than, y =2x+1

=2 * (-3)+1

= -6+1

-5

hence, the required answer is - 5

I found any one solution of given question.

7 0

3 years ago

(1+cos2x)/(1-cos2x) = cot^2x

sesenic [268]

We will turn the left side into the right side.

$\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x$

Use the identity:

$\cos 2x = \cos^2 x - \sin^2 x$

$\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x$

$\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x$

Now use the identity

$\sin^2 x + \cos^2 x = 1$ solved for sin^2 x and for cos^2 x.

$\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x$

$\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x$

$\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x$

$\cot^2 x = \cot^2 x$

8 0

3 years ago