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mixas84 [53]
3 years ago
7

Evaluate when x= 10, 6, 2, 0, -2, -6, -10. (-3, X<-3 1) w(x) = {1, -3 (-5, x>3

Mathematics
1 answer:
Goshia [24]3 years ago
8 0

Answer:

...

Step-by-step explanation:

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9.268

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In a candy mix there are 4 green bars for every 3 red bars. How many red bars are there if there are 200 green bars
erastovalidia [21]

Answer:

Since there are 4 green bars for every 3 red bars and we are trying to find the number of red bars if there are 200 green bars, we can create the ratio:

4 x : 3 y

Where  x  is equal to the number of green bars and  y is the number of red bars.

We know the number of green bars is equal to 200, so we can divide it by 4, giving us:

200 /4=50

Then we can solve for  y , the number of red bars.

// Multiple y  by 50

3 ⋅ 50 = 150

So for every 4 green bars, there are 3 red bars.

For every 200 green bars, there are 150 red bars

Step-by-step explanation:

3 0
3 years ago
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PLEASE HELP WILL MARK YOU BRAINLIEST
gavmur [86]

Answer:

90 degrees

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if The protractor were on the line I’d be able to see if it’s accurately 90

8 0
3 years ago
A restaurant menu has five kinds of soups, seven kinds of main courses, six kinds of desserts, and five kinds of drinks. If a cu
ryzh [129]

Answer: 1050

Step-by-step explanation:

Number of combinations of selecting r things out of n = ^nC_r=\dfrac{n!}{r!(n-r)!}

such that ^nC_1=n

Given: A restaurant menu has 5 kinds of soups, 7kinds of main courses, 6 kinds of desserts, and 5 kinds of drinks.

If a customer randomly selects one item from each of these four categories, then by fundamental counting principle , the number of different outcomes are possible = ^5C_1\times \ ^7C_1\times\ ^6C_1\times\ ^5C_1 =5\times7\times6\times5=1050

hence, total number of outcomes = 1050

3 0
3 years ago
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