Part A) Find BC, the distance from Tower 2 to the plane, to the nearest foot.
in the triangle ACD
sin16=CD/(7600+BD)--------> CD=sin16*(7600+BD)---------> equation 1
in the triangle BCD
sin24=CD/BD-----------> CD=sin24*BD---------------> equation 2
equation 1=equation 2
sin16*(7600+BD)=sin24*BD-----> sin16*7600+sin16*BD=sin24*BD
sin24*BD-sin16*BD=sin16*7600----> BD=[sin16*7600]/[sin24-sin16]
BD=15979 ft
in the triangle BCD
cos24=BD/BC---------> BC=BD/cos24-------> 15979/cos24-------> 17491
BC=17491 ft
the answer part 1) BC is 17491 ft
Part 2) Find CD, the height of the plane from the ground, to the nearest foot.
CD=sin24*BD ( remember equation 2)
BD=15979 ft
CD=sin24*15979 -----------> CD=6499 ft
the answer part 2) CD is 6499 ft
Answer:
parallel = same slope (-2x)
so it's y=-2x + b
let's find b by plugging in 1 for x and 3 for y (the coordinates)
3 = -2*1 + b
3 = -2 + b
5 = b
there you have it:
y = -2x +5
brainliest would really be appropriated (possible when someone else also leaves an answer)
51 x 8 = 408
It can be in this way: 51*8=408
Answer:
hindi ko ma intindihan jknjjj
Answer: 1 11/16
Step-by-step explanation:
5 divided by 5 is 1 so that’s a whole number and 11 is left 16-5=11 so the fraction will be the mixed number as 1 11/16. And also if you can, can you plz help me on my science hw it’s due tomorrow and I don’t know what to do!
