Let
x-----------> first <span>odd integer
x+2--------> second consecutive odd integer
x+4-------> third consecutive odd integer
we know that
(x+4)</span>²=15+x²+(x+2)²-------> x²+8x+16=15+x²+x²+4x+4
x²+8x+16=19+2x²+4x-------> x²-4x+3
x²-4x+3=0
using a graph tool----------> to calculate the quadratic equation
see the attached figure
the solution is
x=1
x=3
the answer is
the first odd integer x is 1
the second consecutive odd integer x+2 is 3
the third consecutive odd integer x+4 is 5
Answer:
C
Step-by-step explanation:
Hello from MrBillDoesMath!
Answer: B
Remark: It is customary to use x^2, not x2, to indicate the square of x.
Discussion:
(4x + 3) ^ 2= ( 4x)^2 + 2 * (4x)(3) + 3^2 =
16 x^2 + 24x + 9
Thank you,
MrB
Answer:
I think it might be -2....
4.30 unless it means up a whole number so that would be 5.0