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CaHeK987 [17]
4 years ago
5

I NEED THE ANSWER PLEASE

Mathematics
1 answer:
Vinvika [58]4 years ago
5 0
You add the given areas together (15.9+19.6+17.5) so the answer is 53.
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Vincent needs 20 inches of wood to makeOne shelf. How many feet of wood does Vincent need to make 6 shelves
butalik [34]

Answer:

10 feet

Step-by-step explanation:

  1. Multiply 20 by 6 which will give the answer 120 (in inches).
  2. Then convert 120(inches) to feet by dividing with 12.
  3. The answer will be 10(feet) needed for six shelves.

20x6= 120

120/12=10

=10 ft

6 0
3 years ago
Sarah visited a tree nursery. She measured and recorded the heights of some young trees. This line plot shows her results. How m
nevsk [136]
2 3/4 because if you do the math good you get this
6 0
3 years ago
Bottles filled by a certain machine are supposed to contain 12 oz of liquid. In fact the fill volume is random with mean 12.01 o
stepan [7]

Answer:

27.43% probability that the mean volume of a random sample of 144 bottles is less than 12 oz.

Step-by-step explanation:

To solve this problem, it is important to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 12.01, \sigma = 0.2, n = 144, s = \frac{0.2}{\sqrt{144}} = 0.0167

What is the probability that the mean volume of a random sample of 144 bottles is less than 12 oz

This is the pvalue of Z when X = 12

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{12 - 12.01}{0.0167}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743.

So there is a 27.43% probability that the mean volume of a random sample of 144 bottles is less than 12 oz.

4 0
3 years ago
Find the difference.
Vsevolod [243]

5.\\12\dfrac{3}{10}-7\dfrac{7}{10}=11\dfrac{10+3}{10}-7\dfrac{7}{10}=11\dfrac{13}{10}-7\dfrac{7}{10}=4\dfrac{6}{10}=4\dfrac{6:2}{10:2}=\boxed{5\dfrac{3}{5}}\\\\11-7=4\\\\\dfrac{13}{10}-\dfrac{7}{10}=\dfrac{13-7}{10}=\dfrac{6}{10}\\\\6.\\8\dfrac{1}{6}-3\dfrac{5}{6}=7\dfrac{6+1}{6}-3\dfrac{5}{6}=7\dfrac{7}{6}-3\dfrac{5}{6}=(7-3)+\dfrac{7-5}{6}=4\dfrac{2}{6}=4\dfrac{2:2}{6:2}=\boxed{4\dfrac{1}{3}}

9.\\7\dfrac{1}{6}-2\dfrac{5}{6}=6\dfrac{6+1}{6}-2\dfrac{5}{6}=6\dfrac{7}{6}-2\dfrac{5}{6}=(6-2)+\dfrac{7-5}{6}=4\dfrac{2}{6}=\boxed{4\dfrac{1}{3}}\\\\10.\\9\dfrac{3}{12}-4\dfrac{7}{12}=8\dfrac{12+3}{12}-4\dfrac{7}{12}=8\dfrac{15}{12}-4\dfrac{7}{12}=(8-4)+\dfrac{15-7}{12}=4\dfrac{8}{12}\\\\=4\dfrac{8:4}{12:4}=\boxed{4\dfrac{2}{3}}

5 0
3 years ago
We would like to estimate the proportion of UF students who owns a scooter to within 1% of the truth, with 95% confidence. We do
professor190 [17]

Answer:

Option A) 9604

Step-by-step explanation:

We are given the following in the question:

Confidence level = 95%

Standard error = 1%

p = q = 0.5

Formula for sample size:

n = (z_{stat}\times \dfrac{p(1-p)}{\text{Standard error}})^2

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting values, we get,

n = (1.96\times \dfrac{0.5(1-0.5)}{0.01})^2 = 9604

Thus, the sample size must be

Option A) 9604

8 0
3 years ago
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