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andrey2020 [161]
3 years ago
11

A polynomial function with a leading coefficient of 1 and multiplicity 1 for each root has these zeros:

Mathematics
1 answer:
Gala2k [10]3 years ago
6 0

Answer:

1.

x - 2 \sqrt{11}

2.

x + 2 \sqrt{11}

5.

x - 4

Step-by-step explanation:

It is correct on Edge!

Give thanks please!

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Find the equation of the line which passes through the point
sammy [17]

Answer:

y= \frac{1}{5}x- \frac{56}{5}

Step-by-step explanation:

We want to find the equation of the line that goes through: !6,-10) and is perpendicular to the line

5x + 3y = 2y - 3

Let's simplify the equation of the line to get:

3y - 2y = - 5x + 3

y = - 5x + 3

The slope of this line is -5.

The perpendicular to this line has a slope of

\frac{1}{5}

The equation going through (6,-10) is

y=m(x-x_1)+y_1

We substitute to get;

y= \frac{1}{5} (x-6) - 10

Expand;

y= \frac{1}{5}x- \frac{6}{5}  - 10

y= \frac{1}{5}x- \frac{56}{5}

7 0
3 years ago
There are values of t so that sin t=.35 and cos t=.6
NISA [10]

Recall the fundamental rule of trig:

\sin^2(x)+\cos^2(x)=1 \quad\forall x \in \mathbb{R}

So, there exists an angle t such that

(0.6,0.35)=(\sin(t),\cos(t))

if and only if

\sin^2(t)+\cos^2(t)=0.6^2+0.35^2=1

Working out the numbers, we get

0.6^2+0.35^2=0.36+0.1225=0.4825\neq 1

So, there doesn't exist a number t such that

(0.6,0.35)=(\sin(t),\cos(t))

7 0
3 years ago
5) -8x – 6 y = 13<br> 4x+3y=-9
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Answer:

no solution exists

Step-by-step explanation:

4 0
3 years ago
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kotykmax [81]
Here ya go
Math.way is the way to go ^v^
Hope ya have a good one

6 0
3 years ago
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