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3 years ago

1.How many grams of zinc Zn and oxygen O2 will be needed to form 324 grams of ZnO after the reaction?

Chemistry

1 answer:

Murrr4er [49]3 years ago

6 0

Answer: pretty sure its 0.214 moles * 40.3g/mole = 8.6g (2 sig figs) of MgO, and

0.035 moles * 40.3g/mole = 1.4g of MgO

Explanation:

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What is the boiling point for water

drek231 [11]

Answer: 100 degrees Celsius and 212 degrees Fahrenheit.

3 0

3 years ago

Someone explain it plz

timofeeve [1]

Answer:

1). 1 mole of Carbon burnt in air

C + O2 →CO2

1 mole of carbon produces 1 mole of CO2 which is 44g of CO2

2). 1 mole of carbon is burnt in 16g of dioxygen

32g of O2 = 44g of CO2

1g of O2 = 44/32

CO2 (Dioxygen is limiting reagent)

16g of O2 = 4/32 × 16 = 22g of CO2 in one mole

3) 2 moles of Carbon burnt in 16g of dioxygen

16g of dioxygen is available, and thus it can combine with 0.5 mol of carbon to give 22g of CO2

4 0

3 years ago

Read 2 more answers

What type of compound is created when potassium and chlorine combine explain how they combine and write the chemical formula. Ne

Elodia [21]

Answer : Ionic compound is created when potassium and chlorine combine. The chemical formula of the compound is KCl.

Explanation :

When potassium and chlorine combine then the type of compound created is Ionic compound.

Ionic compound : These are those compounds which are made of a metal element and non-metal element. Salts are ionic compound which consists of a positive and negative ions.

The electronic configuration of Potassium is,

$1s^22s^22p^63s^23p^64s^1$

The electronic configuration of Chlorine is,

$1s^22s^22p^63s^23p^5$

From this we conclude that the potassium atom is a metal which has 1 electron in their valence shell and chlorine atom is a non-metal which has 7 electrons in their valence shell. For the complete octet, chlorine atom needs only 1 electron which it receives from the potassium atom.

During this process, potassium atom will loses 1 electron and acquire positive charge and chlorine atom will gain 1 electron from potassium atom and acquire negative charge.

$K^++Cl^-\rightarrow KCl$

The chemical formula of the compound is KCl.

5 0

3 years ago

A 14.570 g sample of CaCl2 was added to 12.285 g of K2CO3 and mixed in water. A 3.494 g yield of CaCO3 was obtained.

natta225 [31]

Answer:

Limiting reagent is the potassium carbonate.

Percent yield of calcium carbonate is: 39.3 %

Explanation:

The reaction is:

CaCl₂ + K₂CO₃ → CaCO₃ + 2KCl

Formula for percent yield is:

(Produced yield / Thoeretical yield) . 100

Firstly we determine the moles of each reactant, in order to say what is the limiting reagent: ratio is 1:1.

1 mol of chloride need 1 mol of carbonate.

14.570 g . 1 mol /110.98 g = 0.131 moles of CaCl₂

12.285 g . 1 mol / 138.2g = 0.0889 moles of carbonate.

Limiting reagent is carbonate. For 0.131 moles of CaCl₂ we need the same amount of carbonate and we have less moles.

Ratio is also 1:1, with calcium carbonate.

1 mol of potassium carbonate produces 1 mol of calcium carbonate

then, 0.0889 moles will produce the same amount of CaCO₃

We convert moles to mass: 0.0889 mol . 100.08g /mol = 8.89 g

That's the theoretical yield; to find the percent yield:

(3.494 g / 8.89g) . 100 = 39.3%

7 0

3 years ago

How many moles of oxygen are needed to completey react with 9.5g of sodium

Harlamova29_29 [7]

0.1033 moles of oxygen is needed to completely react with 9.5 G of Na.

7 0

2 years ago