How many moles of oxygen are needed to completey react with 9.5g of sodium

Revise sentence 2 by adding the correct pronoun.

Sidana [21]

Answer:

his, her

Explanation:

edginuity

3 0

3 years ago

Read 2 more answers

Tom [10]

Answer:

5.87 ×10¹⁹ molecules.

Explanation:

From the question given above, the following data were obtained:

Mass of C₆H₅NO₂ = 12 mg

Number of molecules of C₆H₅NO₂ =?

Next, we shall convert 12 mg to g. This can be obtained as follow:

1 mg = 10¯³ g

Therefore,

12 mg = 12 mg × 10¯³ g / 1 mg

12 mg = 0.012 g

Next, we shall determine the mass of 1 mole of C₆H₅NO₂. This can be obtained as follow:

1 mole of C₆H₅NO₂ = (12×6) + (5×1) + 14 + (16×2)

= 72 + 5 + 14 + 32

= 123 g

Finally, we shall determine the number of molecules present in 12 mg (i.e 0.012 g) of C₆H₅NO₂. This can be obtained as follow:

From Avogadro's hypothesis,

1 mole of C₆H₅NO₂ = 6.02×10²³ molecules

123 g of C₆H₅NO₂ = 6.02×10²³ molecules

Therefore,

0.012 g of C₆H₅NO₂ = 0.012 × 6.02×10²³ / 123

0.012 g of C₆H₅NO₂ = 5.87 ×10¹⁹ molecules.

Thus, 12 mg (i.e 0.012 g) of C₆H₅NO₂ contains 5.87 ×10¹⁹ molecules.

4 0

3 years ago

A sugar crystal contains approximately 1. 9×1017 sucrose (c12h22o11c12h22o11) molecules. part a what is its mass in mgmg ? expre

yKpoI14uk [10]

Sucrose is a disaccharide, which is a sugar molecule formed from two monosaccharides. In this case, the two monosaccharides are fructose and glucose.

Answer and Explanation:

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4 0

2 years ago

The second-order rate constant for the following gas-phase reaction is 0.041 1/MLaTeX: \cdotâs. We start with 0.438 mol C2F4 in

pantera1 [17]

Answer:

134.8 seconds is the half-life (in seconds) of the reaction for the initial $C_2F_4$ concentration

Explanation:

Half life for second order kinetics is given by:

$t_{\frac{1}{2}=\frac{1}{k\times a_0}$

Integrated rate law for second order kinetics is given by:

$\frac{1}{a}=kt+\frac{1}{a_0}$

$t_{\frac{1}{2}$ = half life

k = rate constant

$a_0$ = initial concentration

a = Final concentration of reactant after time t

We have :

$C_2F_4 \longrightarrow \frac{1}{2} C_4F_8$

Initial concentration of $C_2F_4=[a_o]=\frac{0.438 mol}{2.42 L}=0.1810 mol/L$

Rate constant = k = $0.041 M^{-1} s^{-1}$

$t_{\frac{1}{2}=\frac{1}{k\times a_0}$

$=\frac{1}{0.041 M^{-1} s^{-1}\times 0.1810 mol/L}$

$t_{1/2}=134.8 s$

134.8 seconds is the half-life (in seconds) of the reaction for the initial $C_2F_4$ concentration

3 0

3 years ago

A protein that no longer functions because its shape has changed (e.g., as a result of heating) has been ________.

stellarik [79]

Answer: denatured

Explanation:

To denature a proteins means to subject the protein to a condition that makes the protein to stop functioning as usual. This is usually due to a permanent change in the structure or shape of the protein. A protein may be denatured by change in pH, heat of binding of other molecules to the protein molecule.

6 0

3 years ago