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Akimi4 [234]
3 years ago
6

Helphelphelphelphelphelppppppp

Mathematics
1 answer:
n200080 [17]3 years ago
5 0

Answer:

Step-by-step explaSimplify the equation by finding the square root of both sides. √x2=x √0=0. x=0. Check: 02=0.

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If a line is perpendicular to y=-2/3x+2, will it be perpendicular to 2x+3y=12?
vova2212 [387]

Answer:

<em>3x + 2y = -2 </em>

Step-by-step explanation:

<em>Given Equation is</em> <em>− 2 x  +  3 y  =  12</em>

3 y  = 2 x  +  12

y =  ( 2 /3 )  y  +  12

<em />

<em>Slope of this line is  </em><em>m  =  2/ 3 </em>

<em> Slope of Line A </em><em> m a  =  2 </em>

<em> Slope of Line B  </em><em>m b  =  2/ 3 </em>

<em> Slope of Line C  </em><em>m c  =  − ( 2 /3 ) </em>

<em> Slope of Line D</em>  <em>m d  =  −  ( 3 /2 ) </em>

since  m d  =  − 1 /m  ,  <em>D</em>  is perpendicular to the given line

7 0
3 years ago
Pls help will give brainiest<br> Find the length of A.
Reptile [31]

Answer:

5

Step-by-step explanation:

13^2=169

12^2=144

169-144=25

Root 25 is 5

7 0
3 years ago
Read 2 more answers
A plant grows 3 centimeters in 10 days. How much does it grow per day? Write your answer as a fraction in simplest form
ira [324]
10d = 3
d = 3/10
Grows 3/10cm per day
4 0
3 years ago
Read 2 more answers
In which quadrant is the number –14 – 5i located on the complex plane?
tino4ka555 [31]

Answer:

3rd Quadrant

Step-by-step explanation:

The "i" in complex numbers behave same as the y in real numbers, so basically this number translated in real would be same as (-14,-5).

To graph this, we have to go -14 units in x direction and -5 units in y direction. Basically, 14 units to the left and then 5 units down. That will place us in 3rd quadrant.

<em>Hence, -14 -5i will fall in the 3rd quadrant of the complex plane.</em>

5 0
4 years ago
Iridium -192 has a half life of 74 days after 148 days, how many milligrams of 900 mg sample will remain?
Ad libitum [116K]
\bf \textit{Amount for Exponential Decay using Half-Life}&#10;\\\\&#10;A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{initial amount}\to &900\\&#10;t=\textit{elapsed time}\to &148\\&#10;h=\textit{half-life}\to &74&#10;\end{cases}&#10;\\\\\\&#10;A=900\left( \frac{1}{2} \right)^{\frac{148}{74}}\implies A=900\left( \frac{1}{2} \right)^2\implies A=225
8 0
4 years ago
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