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Burka [1]
3 years ago
14

1. Jim traveled at a speed of 18km/h for 2 hours .What was the distance covered?

Mathematics
1 answer:
lapo4ka [179]3 years ago
4 0

Answer:

Step-by-step explanation:

1. The formula for distance=speed X time

18 X 2 X3600=129600km/s

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2 to the power of negative 2​
olganol [36]
2^-2 would become 1/2^2 which becomes 1/4.
6 0
2 years ago
Read 2 more answers
At 6:00 A.M. the temperature was 33°F. By noon the temperature had increased by 10°F and by 3:00 P.M. it had increased another 1
chubhunter [2.5K]

So let's see here...


6:00 A.M. temperature is 33°F.

12:00 P.M temperature increased by 10°F making it 43°F.

3:00 P.M. temperature increased by another 12°F making it 55°F.

At 10:00 P.M it would decrease by 15°F making it 40°F.

The temperature would need to fall (or decrease) by 7°F to reach the original temperature of 33°F

Hope this helped!


3 0
2 years ago
Help!<br> What would d be?
Oxana [17]

Answer:

d = 17.5499287748 inches or 17.5 inches to 1 decimal place

Step-by-step explanation:

find the diagonal line passing through the middle of the bottom rectangle:

a² + b² = c²

10² + 8² = c²

100 + 64 = 164

c² = 164

c = √164

c = 12.8062484729

find d:

a² + b² = c²

12² + 12.80624847298² = c²

144+ 164 = 308

c² = 308

c = √308

c = 17.5499287748

therefore d = 17.5499287748 inches or 17.5 inches to 1 decimal place

6 0
3 years ago
Help help help help help Select the equivalent expression (3^2x5^3
swat32

Answer:

D

Step-by-step explanation:

(3^2x5)^3=91125

3^6x5^3=91125

5 0
2 years ago
Read 2 more answers
The weights of red delicious apples are approximately normally distributed with a mean of 9 Ounces and a standard deviation of 0
Simora [160]

Answer:

The mean of W is 55 ounces.

The standard deviation of W is 4.33 ounces.

Step-by-step explanation:

Let X: weight of a red delicious apple, and B: the weight of the box and packing material.

The distribution that will represent W: the total weight of the packaged 5 randomly selected apples will be also normally distributed.

Applying the property of the mean: E(aX)=aE(X), the mean of W will be:

\mu_W=E(W)=E(5X+B)=5E(X)+E(B)=5*9+10=45+10=55

Applying the property of the variance: V(aX+b)=a^2V(X), the variance of W will be:

\sigma^2_W=V(W)=V(5X+B)=5^2V(X)+V(B)=25*0.75+0=18.75

The mean standard deviation of W will be the squared root of V(W):

\sigma_W=\sqrt{V(W)}=\sqrt{18.75}=4.33

The mean of W is 55 ounces.

The standard deviation of W is 4.33 ounces.

3 0
3 years ago
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