1. Jim traveled at a speed of 18km/h for 2 hours .What was the distance covered?
1 answer:
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(See attached formula)
Years = log (total / principal) / n*log(1 + rate/n) where n = compounding periods per year
Years = log (total / principal) / n*log(1 + rate/n)
Rate of .75% = .0625 per month
We'll say we want total = 200 and principal = 100
Years = log (200 / 100) / 12*log(1 + rate/n)
Years = log (2) / 12 * log (1 + .0625/12)
Years = <span> <span> <span> 0.3010299957 </span> </span> </span> / 12 * <span> <span> <span> 0.0022560803 </span> </span> </span> <span><span> </span> </span>
Years = <span> <span> 0.3010299957 </span> </span> / <span> <span> <span> 0.0270729635 </span>
Years = </span></span><span><span><span>11.1192110871 </span> </span> </span>
I don't think that's right
The interest rate is REALLY low. (Less than 1%)
Rate = .75 and .0075 when in a formula
Years = log (2) / 12 * log (1 + .0075/12)
Years = log (2) / 12 * log( <span>1.000625</span>)
Years = <span> <span> <span> 0.3010299957 </span> </span> </span> / 12 * <span> <span> <span> 0.0002713493 </span> </span> </span>
Years = <span><span><span> <span> 0.3010299957 </span> </span> / 0.0032561912 </span>
</span>Years = <span><span><span>92.4485010892
THAT seems a more likely answer with such a low interest rate.
</span> </span> </span>
Years = log (total / principal) / n*log(1 + rate/n) where n = compounding periods per year
Years = log (total / principal) / n*log(1 + rate/n)
Rate of .75% = .0625 per month
We'll say we want total = 200 and principal = 100
Years = log (200 / 100) / 12*log(1 + rate/n)
Years = log (2) / 12 * log (1 + .0625/12)
Years = <span> <span> <span> 0.3010299957 </span> </span> </span> / 12 * <span> <span> <span> 0.0022560803 </span> </span> </span> <span><span> </span> </span>
Years = <span> <span> 0.3010299957 </span> </span> / <span> <span> <span> 0.0270729635 </span>
Years = </span></span><span><span><span>11.1192110871 </span> </span> </span>
I don't think that's right
The interest rate is REALLY low. (Less than 1%)
Rate = .75 and .0075 when in a formula
Years = log (2) / 12 * log (1 + .0075/12)
Years = log (2) / 12 * log( <span>1.000625</span>)
Years = <span> <span> <span> 0.3010299957 </span> </span> </span> / 12 * <span> <span> <span> 0.0002713493 </span> </span> </span>
Years = <span><span><span> <span> 0.3010299957 </span> </span> / 0.0032561912 </span>
</span>Years = <span><span><span>92.4485010892
THAT seems a more likely answer with such a low interest rate.
</span> </span> </span>
The statements that describe the given inequality are as follows:
- Riley wants to save at least $350. She earns $10 each week walking dogs. She has $75 saved. How many weeks will Riley need to walk dogs?
- Elijah would like to have at least $350 to take on vacation for spending money. He already saved $75 and plans to save $10 per week from his weekly paycheck. When will Elijah have enough money to go on vacation?
The inequality is given by:
It means that the sum of a fixed amount of 75 plus a variable amount of 10 has to be of at least 350.
Hence, the 2nd and the 3rd options are correct.
More can be learned about inequalities at brainly.com/question/25235995