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madreJ [45]
3 years ago
12

The maximum number of students in a classroom

Mathematics
2 answers:
Crazy boy [7]3 years ago
8 0
10 students can join the class without exceeding the maximum
marta [7]3 years ago
6 0

Answer:

10 students

Step-by-step explanation:

The maximum number is 26 and 16 have already signed up so in order to know how many can join without exceeding the maximum. You subtract 16 from 26. which then leaves you with 10

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Draw a pair of supplementary adjacent angles. One of the angles should have a measure of 85 degrees. How should the supplementar
Orlov [11]

Supplementary adjacent angles form a "linear pair." Together, they make a line. The angle supplementary to 85° will be slightly obtuse, just as 85° is slightly acute.

4 0
3 years ago
What does the following equal? Please help me!
Juli2301 [7.4K]

Answer:

the first answer

Step-by-step explanation:

1/8 of the absolute value is 1/8 positive

anything from the absolute value is positive because absolute value is the value of how far away the number is from zero.

3 0
3 years ago
Read 2 more answers
1.) You (or your parents) purchase a new car for $19,725.00 plus 4.75% sales tax. The down payment is $2,175.00 and you (or your
Helga [31]

Answer:

$936.94

Step-by-step explanation:

Remember, that because you paid $2,175 up front (down payment), you can borrow $2,175 less from the bank to purchase the car. So first step: Take new car price of $19,725.00 and multiply it by the sales tax percentage ($19,725 * 0.0475) to get $936.94 of tax.

4 0
3 years ago
Choose the solution to this inequality. <br><br> 4/3 &lt; − 8/3y
Yuliya22 [10]

Answer:

Rewrite so y is on the left side of the inequality.

−83y>43

Multiply each term by −38 and simplify.

Inequality Form:

y<−1/2

Interval Notation:

(−∞,−1/2)

Step-by-step explanation:

6 0
3 years ago
which of the following gives an equation of a line that passes through the point (6 over 5, -19 over 5) and is parallel to the l
victus00 [196]
One equation for this would be

y = \frac{41}{16} x-\frac{55}{8}

We start by finding the slope between the two points:

m=\frac{y_2-y_1}{x_2-x_1}=\frac{-12-\frac{-19}{5}}{-2-\frac{6}{5}}&#10;\\&#10;\\=(-12+\frac{19}{5}) \div (-2-\frac{6}{5})&#10;\\&#10;\\=(\frac{-60}{5}+\frac{19}{5}) \div (\frac{-10}{5}-\frac{6}{5})&#10;\\&#10;\\=\frac{-41}{5} \div \frac{-16}{5}=\frac{-41}{5} \times \frac{-5}{16}=\frac{41}{16}

A line parallel to this one will have the same slope.  We will use point-slope form to write our equation:

y-y_1=m(x-x_1)&#10;\\&#10;\\y-\frac{-19}{5}=\frac{41}{16}(x-\frac{6}{5})&#10;\\&#10;\\y+\frac{19}{5}=\frac{41}{16}x- \frac{41}{16} \times \frac{6}{5}&#10;\\&#10;\\y+\frac{19}{5}=\frac{41}{16}x-\frac{246}{80}&#10;\\&#10;\\y+\frac{304}{80}=\frac{41}{16}x-\frac{246}{80}&#10;\\&#10;\\y=\frac{41}{16}x-\frac{246}{80}-\frac{304}{80}&#10;\\&#10;\\y=\frac{41}{16}x-\frac{550}{80}&#10;\\&#10;\\y=\frac{41}{16}x-\frac{55}{8}
6 0
3 years ago
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