Answer:
-1 <= x <= 1
Step-by-step explanation:
√((1-2x+x^2)+2-2x^2)
= √((1-x)^2 + 2*(1-x)(1+x) )
điều kiện là 1 - x > =0 và 1+x >=0
giải 2 bất phương trình trên ta thu đc kết ququả
A) We know that

where d

= distance,
v = velocity,
t = time
In this case, d = 2 mi., t = 30 min. So we get

Dividing both sides by 30, we get

Thus a function for his walk would be

where y = distance and x = number of minutes he walks.
b) Domain of a function is a set of x-values on which the function defined. In this case, the number of minutes is 30 at maximum. So the domain of the function is [0, 30].
The solution is where the two lines meet. From the the graph, it looks like
(1, -1)

so the 2nd equation is really the first equation in disguise.
since both equations are the same, that means if you graph them, is just one line pancaked over the other, and the solutions points is every single one on each, namely
infinitely many solutions.
Answer:
Yes it is, You can rearrange the expression to find that y is uniquely determined in terms of x, therefore a function.
Step-by-step explanation: