Ask question

Ask question

All categories

3 years ago

9

How do I subtract 4 5/6 - 1 2/3

1 answer:

olga55 [171]3 years ago

4 0

Convert it into an improper fraction. Find your common denominator then subtract. If this doesn’t help let me know.

You might be interested in

In 2018, Mike Krzyewski and John Calipari topped the list of highest paid college basketball coaches (Sports Illustrated website

expeople1 [14]

From the data given, we estimate the population mean and population standard deviation. Then, we use this estimate to find a 95% confidence interval for the population variance and the population standard deviation.

Sample:

Salaries in millions of dollars: 2.2, 1.5, 0.5, 1.3, 2.4, 1.5, 2.7, 0.3, 2.0, 0.3

Question a:

The mean is the sum of all values divided by the number of values. So

$\overline{x} = \frac{2.2 + 1.5 + 0.5 + 1.3 + 2.4 + 1.5 + 2.7 + 0.3 + 2.0 + 0.3}{10} = 1.42$

The sample mean salary is of 1.42 million.

Question b:

The standard deviation is the square root of the difference squared between each value and the mean, divided by one less than the number of values.

So

$s = \sqrt{\frac{(2.2-1.42)^2 + (1.5-1.42)^2 + (0.5-1.42)^2 + (1.3-1.42)^2 + (2.4-1.42)^2 + (1.5-1.42)^2 + (2.7-1.42)^2 + ...}{9}} = 0.8772$

Thus, the estimate for the population standard deviation is of 0.8772 million.

Question c:

The sample size is $n = 10$

The significance level is $\alpha = 1 - 0.05 = 0.95$

The estimate, which is the sample standard deviation, is of $s = 0.8772$ .

Now, we have to find the critical values for the Pearson distribution. They are:

$\chi^2_{\frac{\alpha}{2},n-1} = \chi^2_{0.025,9} = 19.0228$

$\chi^2_{1-\frac{\alpha}{2},n-1} = \chi^2_{0.975,9} = 2.7004$

The confidence interval for the population variance is:

$\frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2},n-1}} < \sigma^2 < \frac{(n-1)s^2}{\chi^2_{1-\frac{\alpha}{2},n-1}}$

$\frac{9*0.8772^2}{19.0228} < \sigma^2 < \frac{9*0.8772^2}{2.7004}$

$0.3641 < \sigma^2 < 2.5646$

Thus, the 95% confidence interval for the population variance is (0.3641, 2.5646)

Question d:

Standard deviation is the square root of variance, so:

$\sqrt{0.3641} = 0.6034$

$\sqrt{2.5646} = 1.6014$

The 95% confidence interval for the population standard deviation is (0.6034, 1.6014).

For more on confidence intervals for population mean/standard deviation, you can check brainly.com/question/13807706

4 0

3 years ago

What inequality does this number line show?<br> NEED ASAP

Nana76 [90]

Answer:

4 >_ 3

Step-by-step explanation:

4 0

3 years ago

An employee works 22 days per month if they work an average of 8 and a quarter hours per day how many hours do they work per mon

Over [174]

Answer:

181 1/2 hours a month.

Step-by-step explanation:

You multiply the days per month=22

By the hours they work per day=8 1/4

(Optional) You turn 1/4 into .25

Then: 22 × 8.25= 181.5/181 1/2

<u><em>I hope this answer helps you out. Brainliest would be appreciated. Have a very nice day/night.</em></u>

6 0

3 years ago

Convert this improper fraction to a mixed number 12/ 6 ? <br>a. 1 6/6<br>b. 1 2/6<br>c.1 1/3<br>d. 2

kramer

Answer:

Step-by-step explanation:

Ur answer should be D

7 0

4 years ago

Read 2 more answers

Below is the justification for the formula for area of a circle. Which word,

Lelechka [254]

Answer:

product, product is the answer for a.p.e.x

7 0

3 years ago