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3 years ago

Question 20 (1 point)

Chemistry

1 answer:

romanna [79]3 years ago

8 0

Answer:

A. The ratio of the element in glucose is different than in ethanol

Explanation:

The compounds given are;

Glucose C₆H₁₂O₆

Ethanol C₂H₆O

The two compounds given are different from one another. But they have the same elemental composition.

Ethanol is made up of Carbon, hydrogen and Oxygen and so also, Glucose

Now,

The number of atoms in both compounds are different;

Number of atoms

C H O

Glucose 6 12 6

Ethanol 2 6 1

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3 years ago

A sample compound contains 5.723g Ag, 0.852g S and 1.695g O. Determine its empirical formula.

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Answer:

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Explanation:

Formula for the calculation of no. of Mol is as follows:

$mol=\frac{mass\ (g)}{molecular\ mass}$

Molecular mass of Ag = 107.87 g/mol

Amount of Ag = 5.723 g

$mol\ of\ Ag=\frac{5.723\ g}{107.87\ g/mol} =0.05305\ mol$

Molecular mass of S = 32 g/mol

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$mol\ of\ S=\frac{0.852\ g}{32\ g/mol} =0.02657\ mol$

Molecular mass of O = 16 g/mol

Amount of O = 1.695 g

$mol\ of\ O=\frac{1.695\ g}{16\ g/mol} =0.10594\ mol$

In order to get integer value, divide mol by smallest no.

Therefore, divide by 0.02657

$Ag, \frac{0.05305}{0.02657} \approx 2$

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Therefore, empirical formula of the compound = $Ag_2SO_4$

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4 years ago

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2 years ago