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zepelin [54]
3 years ago
15

Question 20 (1 point)

Chemistry
1 answer:
romanna [79]3 years ago
8 0

Answer:

A. The ratio of the element in glucose is different than in ethanol

Explanation:

The compounds given are;

      Glucose      C₆H₁₂O₆

     Ethanol         C₂H₆O

The two compounds given are different from one another. But they have the same elemental composition.

   Ethanol is made up of Carbon, hydrogen and Oxygen and so also, Glucose

Now,

  The number of atoms in both compounds are different;

                                   Number of atoms

                        C                             H                     O

Glucose           6                             12                      6

Ethanol            2                              6                       1

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schepotkina [342]

Answer:

in solution of PH4 it is red

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2 years ago
How to solve 2=-log(x)
ch4aika [34]

First, you want to extract the negative from -log(x).

So now you have log(x) = -2

Now you have to use the property loga(x)=b is the same as x=a^2

So now, it is x = 10^-2. Remember that when there is just a log, it is implied that it is ‘a’ is 10.

Then you evaluate the negative square to 1/10^2

Answer is 1/100

8 0
3 years ago
As carbon dioxide enters systemic blood, it causes more oxygen to dissociate from hemoglobin, which in turn allows more CO2 to c
vagabundo [1.1K]

Answer:

The correct answer is "False".

Explanation:

It is false that as carbon dioxide enters systemic blood, it causes more oxygen to dissociate from hemoglobin. Once an atom of oxygen binds to hemoglobin, hemoglobin change its shape and makes easier than a second and a third atom of oxygen binds towards it. This change in conformation makes no possible that carbon dioxide can cause that oxygen dissociates from hemoglobin.

5 0
3 years ago
Be sure to answer all parts.The equilibrium constant, Kc, for the formation of nitrosyl chloride from nitric oxide and chlorine,
djverab [1.8K]

<u>Answer:</u> The reaction proceeds in the forward direction

<u>Explanation:</u>

For the given chemical equation:

2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)

Relation of K_p\text{ with }K_c is given by the formula:

K_p=K_c(RT)^{\Delta n_g}

where,

K_p = equilibrium constant in terms of partial pressure = ?

K_c = equilibrium constant in terms of concentration = 6.5\times 10^4

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature = 35^oC=[35+273]K=308K

\Delta n_g = change in number of moles of gas particles = n_{products}-n_{reactants}=2-3=-1

Putting values in above equation, we get:

K_p=6.5\times 10^4\times (0.0821\times 500)^{-1}\\\\K_p=1583.43

K_p is the constant of a certain reaction at equilibrium while Q_p is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

The expression of Q_p for above equation follows:

Q_p=\frac{(p_{NOCl})^2}{p_{Cl_2}\times (p_{NO})^2}

We are given:

p_{NOCl}=1.76atm

p_{NO}=1.01atm

p_{Cl_2}=0.42atm

Putting values in above equation, we get:

Q_p=\frac{(1.76)^2}{0.42\times (1.01)^2}=7.23

We are given:

K_p=1583.43

There are 3 conditions:

  • When K_{p}>Q_p; the reaction is product favored.
  • When K_{p}; the reaction is reactant favored.
  • When K_{p}=Q_p; the reaction is in equilibrium

As, K_p>Q_p, the reaction will be favoring product side.

Hence, the reaction proceeds in the forward direction

4 0
2 years ago
How does one calculate the pH of a solution? O A. The pH is the product of [H+] and [OH-]. O B. The pH is the negative log of [O
blagie [28]

Answer:

I believe it is A

Explanation:

pH = -log[H+] and pOH = -log[OH−].    

8 0
2 years ago
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