The missing labels are:
- CuCO₃(s), H₂SO₄(aq): reactants.
- +: plus sign.
- CuSO₄(aq), H₂O(l), CO₂(g): products.
- (s): solid.
- (aq): aqueous.
- (l): liquid.
- (g): gaseous.
<h3>What is a chemical equation?</h3>
It is a way to represent a chemical reaction.
Let's consider the following chemical equation.
CuCO₃(s) + H₂SO₄(aq) → CuSO₄(aq) + H₂O(l) + CO₂(g)
The missing labels are:
- CuCO₃(s), H₂SO₄(aq): reactants. They are on the left side of the equation.
- +: plus sign. It separates substances.
- CuSO₄(aq), H₂O(l), CO₂(g): products. They are on the right side of the equation.
- (s): solid.
- (aq): aqueous.
- (l): liquid.
- (g): gaseous.
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Answer:
Option D is correct = 58 g
Explanation:
Data Given:
mass of LiOH = 120 g
Mass of Li3N= ?
Solution:
To solve this problem we have to look at the reaction
Reaction:
Li₃N (s) + 3H₂0 (l) -----------► NH₃ (g) + 3LiOH (l)
1 mol 3 mol
Convert moles to mass
Molar mass of LiOH = 24 g/mol
Molar mass of Li₃N = 35 g/mol
So,
Li₃N (s) + 3H₂0 (l) -----------► NH₃ (g) + 3LiOH (l)
1 mol (35 g/mol) 3 mol (24 g/mol)
35 g 72 g
So if we look at the reaction 35 g of Li₃N react with water and produces 72 g of LiOH , then how many g of Li₃N will be react to Produce by 120 g of LiOH
For this apply unity formula
35 g of Li₃N ≅ 72 g of LiOH
X of Li₃N ≅ 120 g of LiOH
By Doing cross multiplication
Mass of Li₃N = 35 g x 120 g / 72 g
mass of Li₃N = 58 g
120 g of LiOH will produce from 58 g of Li₃N
So,
Option D is correct = 58 g
Answer:Why is Dalton credited with proposing the first atomic theory if Democritus was talking about atoms almost 2,200 years earlier?
- Democritus' ideas were not supported by evidence
- Dalton's theory was the first scientific theory because it relied on scientific investigative processes.
- Dalton's theory was supported by evidence and repeated investigation.
Explanation: 1: Democritus' ideas were not supported by evidence
2: Dalton's theory was the first scientific theory because it relied on scientific investigative processes.
3: Dalton's theory was supported by evidence and repeated investigation.
The principal quantum number (n): specifies the principal shell of the orbital.
The answer is option D.
The important quantum number (n) describes the dimensions of the orbital. Orbitals for which n = 2 are larger than those for which n = 1, as an example. Because they have got opposite electric costs, electrons are interested in the nucleus of the atom.
The numerals, called essential quantum numbers, imply strength degrees as well as the relative distance from the nucleus. A 1s electron occupies the energy stage nearest the nucleus.
A 2s electron, less strongly certain, spends most of its time farther far from the nucleus.
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