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alexdok [17]
3 years ago
9

ITS Urgent.jjdjwjehvd​

Mathematics
1 answer:
kramer3 years ago
8 0
D, it is term number 4....
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Plz answer these questions. If ur gonna answer answer them all or else i will report and u wont get brainliest.
o-na [289]

Answer:

Step-by-step explanation:

8 0
2 years ago
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Express as a trinomial: (2x-3)(x 5)
Illusion [34]
I am assuming the expression is (2x-3)(x+5) or (2x-3)(x-5). I will teach you how to solve for both as I am not sure which one you are asking for. There are 4 steps to multiplying.

1) Multiply the x times the second x
2) Multiply x times the second number
3) Multiply the number by the second x
4) Multiply the number by the second number.

(2x*x)+(2x*5)+(-3*x)+(-3*5)=(2x^{2})+(10x)+(-3x)+(-15)=2x^{2}+7x-15

(2x*x)+(2x*-5)+(-3*x)+(-3*-5)=(2x^{2})+(-10x)+(-3x)+(15)=2x^{2}-13x+15

Your answer is 2x^{2}+7x-15 or 2x^{2}-13x+15. Does that answer your question?
6 0
3 years ago
What is the sum of the roots of the polynomial shown below?<br> f(x) = x^3 + 2x^2 - 11x-12
svp [43]

<u>Answer:  </u>

Sum of the roots of the polynomial x^{3}+2 x^{2}-11 x-12 \text { is }-2

<u>Solution:</u>

The general form of cubic polynomial is a x^{3}+b x^{2}+c x+d=0 ---- (1)

If we have any cubic polynomial a x^{3}+b x^{2}+c x+d=0 having roots \alpha , \beta , \theta

Sum of roots \alpha + \beta + \theta = \frac{-b}{a} ---(2)

From question given that,

x^{3}+2 x^{2}-11 x-12 --- (3)

On comparing equation (1) and (3), we get a = 1, b = 2, c = -11 and d = -12

Hence the sum of roots using eqn 2 is given as,

= \frac{-2}{1}

= -2

Hence the sum of the roots of the polynomial x^{3}+2 x^{2}-11 x-12 \text { is }-2

4 0
2 years ago
What is 1x1? please help me lol
Ksju [112]

Answer:

1

Step-by-step explanation:

1 times anything is itself

you're welcome

7 0
3 years ago
Read 2 more answers
Helppppppppppppppppppppppppp
Rasek [7]

Answer:

A  40

Step-by-step explanation:

We can find angle K

J + K + L = 180  The angles of a triangle add to 180

50 + K + 90 =180

140 +K = 180

Subtract 140 from each side

140-140 + K = 180-140

K = 40

Since the triangles are congruent

J = P

K = N

L = M

We want to find N

K = N = 40

K = N

4 0
2 years ago
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