I am assuming the expression is (2x-3)(x+5) or (2x-3)(x-5). I will teach you how to solve for both as I am not sure which one you are asking for. There are 4 steps to multiplying.
1) Multiply the x times the second x
2) Multiply x times the second number
3) Multiply the number by the second x
4) Multiply the number by the second number.
(2x*x)+(2x*5)+(-3*x)+(-3*5)=(2

)+(10x)+(-3x)+(-15)=2

+7x-15
(2x*x)+(2x*-5)+(-3*x)+(-3*-5)=(2

)+(-10x)+(-3x)+(15)=2

-13x+15
Your answer is 2

+7x-15 or 2

-13x+15. Does that answer your question?
<u>Answer: </u>
Sum of the roots of the polynomial 
<u>Solution:</u>
The general form of cubic polynomial is
---- (1)
If we have any cubic polynomial
having roots 
Sum of roots
=
---(2)
From question given that,
--- (3)
On comparing equation (1) and (3), we get a = 1, b = 2, c = -11 and d = -12
Hence the sum of roots using eqn 2 is given as,
=
= -2
Hence the sum of the roots of the polynomial 
Answer:
1
Step-by-step explanation:
1 times anything is itself
you're welcome
Answer:
A 40
Step-by-step explanation:
We can find angle K
J + K + L = 180 The angles of a triangle add to 180
50 + K + 90 =180
140 +K = 180
Subtract 140 from each side
140-140 + K = 180-140
K = 40
Since the triangles are congruent
J = P
K = N
L = M
We want to find N
K = N = 40
K = N