All categories

2 years ago

Given f(x)=2(3)x what f (2)?

Mathematics

1 answer:

Drupady [299]2 years ago

5 0

Answer:

$f(2)=18$

Step-by-step explanation:

Assuming the "x" to be an exponent:

$f(x)=2(3)^x$

$f(2)=2(3)^2$

$f(2)=2(9)$

$f(2)=18$

You might be interested in

The statement tan theta -12/5, csc theta -13/5, and the terminal point determined by theta is in quadrant 2."

Harlamova29_29 [7]

Answer:

Answer C:

Cannot be true because $csc(\theta)$ is greater than zero in quadrant 2.

Step-by-step explanation:

When the csc of an angle is negative, since the cosecant function is defined as:

$csc(\theta)=\frac{1}{sin(\theta)}$

that means that the sin of the angle must be negative, and such cannot happen in the second quadrant. The sine function is positive in the first and second quadrant.

Therefore, the correct answer is:

Cannot be true because $csc(\theta)$ is greater than zero in quadrant 2.

6 0

3 years ago

When the sum of a number and 14 is divided by 3, the result is 4.

kvv77 [185]

Answer:

it is 4.6 sorry girl

Step-by-step explanation:

5 0

3 years ago

Gary is 3 years older than twice the age of His sister Elena which shows an equation for this situation

Lynna [10]

Answer: G = 2E + 3

Step-by-step explanation:

Let E represent Elena's age.

Then Gary(G) is two times Elena(E) plus 3 --> G = 2E + 3

8 0

3 years ago

The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or

tigry1 [53]

Answer-

The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%

Solution-

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

$P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}$

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}$

$P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67$

Putting these values,

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%$

5 0

3 years ago

Help please will mark brainliest

ipn [44]

Answer:

459

Step-by-step explanation:

27 x 17= 459

3 0

2 years ago