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yKpoI14uk [10]
2 years ago
6

Angles: Arcs & Angles need help thank you!!

Mathematics
1 answer:
torisob [31]2 years ago
3 0

Answer:

See answers below

Step-by-step explanation:

1) The typr of triangle in a semicircle is a right angle. Hence the measure of  m<ABC  is 90degrees

2) m<DEF = 1/2(144)

m<DEF = 144/2

m<DEF = 72degrees

3) From the trinagle

4x+3 + x+7 +90 ==180

5x + 100 = 180

5x = 180-100

5x = 80

x = 80/5

x = 16

<QRD =  x+7

m<QRD = 16 + 7

m<QRD = 23degrees

4)  Angle in the same segment are equal

5x-37= 3x+1

5x - 3x = 1+37

2x = 38

x = 38/2

x =19

arc NM = 2m<P

arc NM = 2(3x+1)

arc NM = 2(3(19)+1)

arc NM = 2(58)

arcNM = 116degrees

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Step-by-step explanation:

We are given midpoint B (x,y)  =(-3,5)

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We have x=-3, x₁=? and x₂= 1

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x=\frac{x_{1}+x_{2}}{2}\\-3=\frac{x_{1}+1}{2}\\-6=x_{1}+1\\-6-1=x_{1}\\x_{1}=-7

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y=\frac{y_{1}+y_{2}}{2}\\5=\frac{y_{1}+-2}{2}\\5*2=y_{1}+-2\\10=y_{1}+-2\\10+2=y_{1}\\y_{1}=12

SO, coordinates of endpoint A are (-7,12)

Keywords: Midpoint of line segment

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