Step-by-step answer:
A line with slope (or gradient) m, passing through a point (x0,y0) can be represented by the equation:
(y-y0) = m(x-x0) ......................(1)
Here,
(x0,y0) = (1,7), and
slope/gradient = -2
Substitute values into (1) above gives
(y-7)=2(x-1)
Expand and simplify
y-7 = 2x-2
y =2x -2 + 7
y=2x+5
is the final answer.
Variable
Step-by-step explanation:
First we need to find the gradient of K
which is y1-y2/x1-x2
(-1,3) and (5,-2)
so it becomes 3-(-2)/-1-5
m=-5/6
when two lines are perpendicular their gradients multiply to make -1
that means the gradient of L has to be 6/5
we can substitute the point on L (5,-2) and the gradient of 6/5 into y=mx+c
-2 = (6/5) x 5 + c
c = -8
the equation of line L is y= 6x/5 -8
Answer:
= 5
Step-by-step explanation:
Substitute the given values into the formula
16 = 
× 4(3 + )
16 = 2(3 + ) ( divide both sides by 2 )
8 = 3 + ( subtract 3 from both sides )
5 =
A) Measure of Angle L is 67.5. Angle F & Angle L are alternate interior angles.
b) Measure of Angle E is 112.5, because we know that F and H are vertical angles, so therefore they’re congruent. We also know H and E are adjacent, so H + E = 180.
c) Angles E and K are alternate exterior angles. Measure of Angle K is 112.5.
d) Measure of Angle H is 67.5, because we know that Angle F, which is vertical to Angle H, is 67.5. Vertical angles are congruent.
e) Measure of Angle I is 112.5, because Angle I and Angle K are vertical angles.
f) They’re corresponding angles.
