All categories

3 years ago

What are most elements on the periodic table?

Physics

2 answers:

Inessa [10]3 years ago

6 0

Answer:

Is metals, Non metals, Metalloids

The periodic table on the left separates elements into three groups : the metals (green in the table), nonmetal (orange), and metalloids (blue) . most elements are metal. they are usually shiny,very dense , and only melt at high temperatures .

Molodets [167]3 years ago

5 0

Answer:

Metals, nonmetals and metalloids.

Explanation:

You might be interested in

A wire carries a current of 0.66 A. This wire makes an angle of 58° with respect to a magnetic field of magnitude 5.50 10-5 T. T

Oliga [24]

Answer:

The length of the wire is "1.93 m".

Explanation:

Given:

Current,

I = 0.66 A

Angle,

$\Theta$ = 58°

Magnetic field of magnitude,

F = $5.5\times 10^{-5}$ N

The length of the wire will be:

⇒ $F = B\times I\times L\times Sin \Theta$

or,

⇒ $L = \frac{F}{B\times I\times Sin \theta}$

By putting the values, we get

$=\frac{5.5\times 10^{-5}}{0.66\times 5.1\times 10^{-5}\times Sin \ 58^{\circ}}$

$=\frac{5.5}{2.828}$

$=1.93 \ m$

6 0

3 years ago

Isobars do not differ in the number of

Elodia [21]

Answer:

don't post irrelevant questions

8 0

3 years ago

Read 2 more answers

If the absolute temperature of a gas is 600 K, the temperature in degrees Celsius is

gavmur [86]

Kelvin is a base unit of temperature scale from SI that defines as zero degree Kelvin (absolute zero). The absolute zero is a hypothetical statement that all molecular movement stops because there is no transient of energy for the molecules to move. When converting temperature in degree Celsius to Kelvin, add 273. You are given 600K and you are asked to find it in degrees Celsius.

T(K) = T(C) + 273
600 K = T(C) + 273
T(C) = 600 – 273
T(C) = 327 °C
<span>The answer is letter B.</span>

6 0

3 years ago

Read 2 more answers

what is the net force required to give an automobile with a mass of 1,600 kg an acceleration of 4.5m/s

Dmitrij [34]

Hi there!

Recall Newton's Second Law:

$\large\boxed{\Sigma F = ma}}$