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chubhunter [2.5K]
4 years ago
11

How are Newton’s second and third laws of motion important to your everyday life?

Physics
1 answer:
Rasek [7]4 years ago
3 0
Well, first off, Newtons second law of motion <span>deals with the motion of accelerating and decelerating objects.
 W</span>e already know that from everyday life examples such as simply pushing a car that if 2 people push a car on a flat road it will accelerate faster than if one person was pushing it... Therefore, there is a relationship between the size of the force and the acceleration.  
 Now onto the third law of motion. First of all, what is the third law of motion? Well, a force is a push or a pull that acts upon an object as a results of its interaction with another object. Forces result from interactions! According to Newtons third law, whenever one object, and another object interact with each other, they exert forces upon each other. "For every action, there is an equal and opposite reaction."  The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. So, how is this important to everyday life you may ask? 
<span>Well, the action-reaction force pairs are found everywhere in your body.
 For example, right now as I am typing, my tendons are exerting forces on bones, and those bones exert reaction forces on the tendons, as muscles contract, pulling my fingers on the keys. I press on those keys, and they press back on my fingers. See? Since i'm pressing on the keys, the press back on me. Its opposite from each other, as stated in the quite above. "</span><span>For every action, there is an equal and opposite reaction." </span>
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Answer:

a: increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object

Explanation:

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3 years ago
A 55 kg roller skater is at rest on a flat skating rink, a 198 N horizontal force is needed to set the skater in motion.
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Answer:

Explanation:

To get the person Moving you have to overcome the static (means not moving) friction coefficient.  U(static)

To get the person going at the same speed you have to overcome the kinetic friction coefficient. U(Kinetic)

Force to get him moving is 198 N.   Force = ma = U(static)Mg

combining the 2 equations you get 198N = U(static)* 55kg *9.8m/s^2   Solve for U(static)

Same equation to keep him moving except with the dynamic force and the dynamic U

 

175N=  U(kinetic)*55kg*9.8m/s^2  Solve (U dynamic)

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3 years ago
• List four uses of the concave mirror.<br> State five uses of lenses in everyday activities
Zina [86]
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6 0
3 years ago
Calculate the velocity of an apple that falls freely from rest and drops for 3.5 seconds.
padilas [110]

Answer:

initial velocity(u)=0

time(t)=3.5sec

acceleration (a)=9.8m/s²

final velocity (v)=?

Explanation:

we have

v=u+at=0+9.8×3.5=34.3m/s

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In short, Your Answer would be Option C

Hope this helps!
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