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chubhunter [2.5K]
4 years ago
11

How are Newton’s second and third laws of motion important to your everyday life?

Physics
1 answer:
Rasek [7]4 years ago
3 0
Well, first off, Newtons second law of motion <span>deals with the motion of accelerating and decelerating objects.
 W</span>e already know that from everyday life examples such as simply pushing a car that if 2 people push a car on a flat road it will accelerate faster than if one person was pushing it... Therefore, there is a relationship between the size of the force and the acceleration.  
 Now onto the third law of motion. First of all, what is the third law of motion? Well, a force is a push or a pull that acts upon an object as a results of its interaction with another object. Forces result from interactions! According to Newtons third law, whenever one object, and another object interact with each other, they exert forces upon each other. "For every action, there is an equal and opposite reaction."  The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. So, how is this important to everyday life you may ask? 
<span>Well, the action-reaction force pairs are found everywhere in your body.
 For example, right now as I am typing, my tendons are exerting forces on bones, and those bones exert reaction forces on the tendons, as muscles contract, pulling my fingers on the keys. I press on those keys, and they press back on my fingers. See? Since i'm pressing on the keys, the press back on me. Its opposite from each other, as stated in the quite above. "</span><span>For every action, there is an equal and opposite reaction." </span>
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How do modern scientist describe the make up of matter
lbvjy [14]

The matter is a collection or composition of extremely small particles called "Atoms".

<u>Explanation</u>:

  • The matter is anything that has mass and which utilizes space by having volume.
  • Modern scientists describe the makeup of matter as a collection of tiny substances called atoms.
  • Matter can either be in solid, liquid, or gaseous state and even appear in plasma form.
  • Matter can neither be created nor be destroyed but only transferred from one form to the other.
  • Atoms are composed protons, neutrons and electrons. The protons and neutrons are contained in the nucleus, while the electrons orbit around the nucleus of the atom.
  • Protons are positively charged, neutrons are neutral and electrons are negative.
4 0
4 years ago
Air is being pumped into a spherical balloon so that its volume increases at a rate of 150 cm3/s. How fast is the radius of the
Slav-nsk [51]

0.119cm/s is the radius of the balloon increasing when the diameter is 20 cm.

<h3>How big is a circle's radius?</h3>

The radius of a circle is the distance a circle's center from any point along its circumference. Usually, "R" or "r" is used to indicate it.

A circle's diameter cuts through the center and extends from edge to edge, in contrast to a circle's radius, which extends from center to edge. Essentially, a circle is divided in half by its diameter.

dv/dt = 150cm³/s

d = 2r = 20cm

r = 10cm

find dr/dt

Given that the volume of a sphere is calculated using

v = 4/3πr³

Consider both sides of a derivative

d/dt(v) = d/dt( 4/3πr³)

dv/dt =  4/3π(3r²)dr/dt = 4πr²dr/dt

Hence,

dr/dt = 1/4πr².dv/dt

dr/dt = 1/4π×(10)²×150

dr/dt = 1/4π×100×150

dr/dt = 0.119cm/s.

To know more about radius visit:

brainly.com/question/15053236

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3 0
1 year ago
a circuit element having terminals a and b has vab = 10v and iba = 2a over a period of 20s, how much charge moves throught the e
PIT_PIT [208]

Answer: charge Q = 40Coulombs

Explanation: The current in a circuit is the quantity of charge that flows through it per second.

Here the 2amp current is same as the amount of charge in coulomb that flows through the terminal in ONE second.

So, if 2 coulomb of charge flows in 1sec then in 20 secs we will have

Q(charge) = 2*20 = 40 coulombs

6 0
3 years ago
A sealed test tube traps 25.0 cm3 of air at a pressure of 1.00 atm and temperature of 18°C. The test tube’s stopper has a diamet
puteri [66]

Answer:

180° C

Explanation:

First we start by finding the area of the stopper.

A = πd²/4, where d = 1.5 cm = 0.015 m

A = 3.142 * 0.015² * ¼

A = 1.767*10^-4 m²

Next we find the force on the stopper

F = (P - P•)A, where

F = 10 N

P = pressure inside the tube,

P• = 1 atm

10 = (P - 101325) * 1.767*10^-4

P - 101325 = 10/1.767*10^-4

P - 101325 = 56593

P = 56593 + 101325

P = 157918 Pascal

Now, remember, in an ideal gas,

P1V1/T1 = P2V2/T2, where V is constant, then we have

P1/T1 = P2/T2, and when we substitute the values, we have

101325/(273 + 18) = 157918/ T2

101325/291 = 157918/ T2

T2 = (157918 * 291)/101325

T2 = 453 K

T2 = 453 - 273 = 180° C

3 0
4 years ago
Which of the things below have matter? There is more than 1 answer.
JulijaS [17]

Answer:

car and a can

Explanation:

3 0
3 years ago
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